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3 years ago

What is the value of 2(x+y)² when X=3 and Y=4 ?

Mathematics

2 answers:

valina [46]3 years ago

8 0

Answer:

Step-by-step explanation:

Given

2(x + y)² ← substitute x = 3 and y = 4 into the expression

= 2(3 + 4)²

= 2(7)²

= 2 × 49

= 98

otez555 [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Step 1: Define

2(x + y)²

x = 3

y = 4

Step 2: Substitute and Evaluate

2(3 + 4)²

2(7)²

2(49)

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murzikaleks [220]

Answer: True

Step-by-step explanation:

Cost = 15 + 3t

22.5 = 15 + 3(2.5)

22.5 = 15 + 7.5

22.5 = 22.5 <— true

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3 years ago

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A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station. Find the ra

Anika [276]

Answer:

The rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

Step-by-step explanation:

Given information:

A plane flying horizontally at an altitude of "1" mi and a speed of "430" mi/h passes directly over a radar station.

$z=1$

$\frac{dx}{dt}=430$

We need to find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.

$y=2$

According to Pythagoras

$hypotenuse^2=base^2+perpendicular^2$

$y^2=x^2+1^2$

$y^2=x^2+1$ .... (1)

Put z=1 and y=2, to find the value of x.

$2^2=x^2+1^2$

$4=x^2+1$

$4-1=x^2$

$3=x^2$

Taking square root both sides.

$\sqrt{3}=x$

Differentiate equation (1) with respect to t.

$2y\frac{dy}{dt}=2x\frac{dx}{dt}+0$

Divide both sides by 2.

$y\frac{dy}{dt}=x\frac{dx}{dt}$

Put $x=\sqrt{3}$ , y=2, $\frac{dx}{dt}=430$ in the above equation.

$2\frac{dy}{dt}=\sqrt{3}(430)$

Divide both sides by 2.

$\frac{dy}{dt}=\frac{\sqrt{3}(430)}{2}$

$\frac{dy}{dt}=372.390923627$

$\frac{dy}{dt}\approx 372$

Therefore the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station is 372 mi/h.

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3 years ago

Help!!!! Volume of a cylinder!!!!

belka [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Aleks [24]

DrH = DrT + 0.019
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3 years ago

Geometric sequences HELP ASAP!

Pani-rosa [81]

Given:

The table for a geometric sequence.

To find:

The formula for the given sequence and the 10th term of the sequence.

Solution:

In the given geometric sequence, the first term is 1120 and the common ratio is:

$r=\dfrac{a_2}{a_1}$

$r=\dfrac{560}{1120}$

$r=0.5$

The nth term of a geometric sequence is:

$a_n=ar^{n-1}$

Where a is the first term and r is the common ratio.

Putting $a=1120, r=0.5$ , we get

$a_n=1120(0.5)^{n-1}$

Therefore, the required formula for the given sequence is $a_n=1120(0.5)^{n-1}$ .

We need to find the 10th term of the given sequence. So, substituting $n=10$ in the above formula.

$a_{10}=1120(0.5)^{10-1}$

$a_{10}=1120(0.5)^{9}$

$a_{10}=1120(0.001953125)$

$a_{10}=2.1875$

Therefore, the 10th term of the given sequence is 2.1875.

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3 years ago