Remark
All three sides are equal in an equilateral triangle.
y + 5 = x + y - 5 . . . . . . .(1)
y +5 = 2x - 7 . . . . . . . . .(2)
For 1
Subtract y from both sides.
5 = x - 5 . . . . . . . . . . . Add 5 to both sides.
x = 10
x + y - 10 = 2x - 7 . . . .Put x = 10 into this equation
10 + y - 10 = 2*10 - 7
y = 20 - 7
y = 13
In 2x - 7, let x = 10
2(10) - 7 = 20 - 7
Answer:
<em>First option: </em> 
Step-by-step explanation:
Given the point-slope equation 
, you need to solve for 
, because you are looking for the equation of the line in slope-intercept form:
Being 
the slope of that line, and 
the intersection of the line with the y-axis.
Then:
Apply Distributive property:
Subtract 7 from both sides:
Rewrite the equation:
(The linear function of the First option)
Answer:
where is the question I want to help you.
For a cyclic quadrilateral
The opposite angles are supplementary (meaning they sum up to 180 °)
I.e (x +20) ° + 3x ° =180 °
20 + 4x = 180
4x=180 - 20
4x = 160
Divide through by 4
x = 40 °
Angle at point A
(2x + 38) = (2(40) + 38) = 118 °
Angle at point B
3x = 3(40) = 120 °
Angle at point D
x + 20 = 40 + 20 = 60 °
Angle at point C
The total angle in a quadrilateral is 360 °
I.e 118 + 120 + 298 +
Answer:
Option 4
Step-by-step explanation:
Trying the first 2 pairs and confirm the Last Option
y=5*2^x
