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sweet-ann [11.9K]
3 years ago
13

Determine if the statement is always, sometimes, or never true:

Mathematics
2 answers:
andrezito [222]3 years ago
7 0
The answer is:  "never".
_____________________________

MissTica3 years ago
6 0

Answer:

never

Step-by-step explanation:

To Find :An equilateral triangle is a right triangle.

              1. always

              2.sometimes

              3.never

Solution :

Definition of equilateral triangles: a triangle having all sides equal in length

Since all sides are equal so by property of triangle (angle opposite to equal sides are equal ) so, all angles are equal .

If equilateral triangle is right angle then one of its angle is of 90°

And in equilatera triangle all angles are equal so all angles must be of 90°

We know that triangle sum property is : Sum of all angles of triangle is equal to 180°

So, 90°+90°+ 90° =180°

⇒270°≠180°

since this violates the angle sum property of triangle .

Thus an equilateral triangle can never be a right triangle

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2(5x-7)=2x+10 what Is the distributive property
professor190 [17]
2(5x)2(-7)=2x+10

2(5x)= 10x
2(-7)=-14

10x-14=2x+10

Solve:
10x-2x=8x

8x-14=10

14+10=24

8x=24

24/8=3

X=3
4 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Please help. My son and I don't get it
vfiekz [6]
So you have 3 and you want to get rid of 2 2/5. 3-2 is 1  1-2/5 is equal to three fifths, which is the answer. 
6 0
3 years ago
Read 2 more answers
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igor_vitrenko [27]
He made a profit of thirty dollars
8 0
3 years ago
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
MAXImum [283]

Answer:

  • x = 15/p
  • x = -3

Step-by-step explanation:

<u>Given expression</u>

  • 4(px+1)=64

<u>Solving for x</u>

  • 4px + 4 = 64
  • 4px = 60
  • px = 15
  • x = 15/p

<u>Value of x when p= - 5</u>

  • x = 15/(-5) = -3
3 0
3 years ago
Read 2 more answers
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