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AURORKA [14]
3 years ago
12

Factor the expression: 84x – 12x

Mathematics
2 answers:
liberstina [14]3 years ago
6 0
Subtract 12x from 84x = 72x
iris [78.8K]3 years ago
3 0
Subtract 84x and 12x from each other to simplify or factor the expression and you get 72x
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If the height and base length of a square pyramid are each doubled, how does the volume of the pyramid change?
Vikentia [17]
It quadruples. (Multiplies by 4)
5 0
3 years ago
X^3 = 1,000<br> algebratic equations
katovenus [111]

Answer:

10

Step-by-step explanation:

x³=1000

x=3√1000

x=10

5 0
3 years ago
Read 2 more answers
if we increased one side of a square by 5 units and decreased the other by 3 units the area of the resulting rectangle would be
zvonat [6]

Answer:

18 units

Step-by-step explanation:

So let's list out the sides.

for the first square let's just call them x

for the second square then they would be x+5 and x-3

So let's write out their areas we will cal the area of the first one z

x*x = z

(x+5)*(x-3) = z+21

since z = x^2 we can set up the second equation as a quadratic.

(x+5)*(x-3) = x^2 + 21

x^2 - 3x + 5x - 15 = x^2 + 21

But look, the x^2s cancel out

2x - 15 = 21

2x = 36

x = 18

Test it out and see if it fits the description, And if you don't understand anything just let me know so I can explain more.  

3 0
3 years ago
Jamie says that the expression 6x-2x+4 and 4(x+1) are not equivalent because one expression has a term that is subtracted and th
Sati [7]

Answer:

1. D 2. A 3. Distribute the four in 4(x+1)

Step-by-step explanation:

1. It says that Jamie is saying that they are "not equivalent".

2. You have to use the distributive property to distribute the 4 to x and to the 1.

3. After distributing, compare the two expressions and now see if they are equivalent or not.

8 0
3 years ago
Condense 2log4 + log3 - log2 + log5
antiseptic1488 [7]

2\log4 + \log3 -\log2 + \log5= \\ \\ = \log 2^4+ \log3 -\log2 + \log5 = \\ \\ = \log 16+ \log3 -\log2 + \log5 = \\ \\ = \log\Big(16\cdot 3:2\cdot 5\Big) = \log\Big(\dfrac{16\cdot 3\cdot 5}{2}\Big) = \log(8\cdot 3\cdot 5) = \\ \\ =\log120

3 0
3 years ago
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