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wel
2 years ago
11

Pls help me out tysm

Mathematics
2 answers:
Nana76 [90]2 years ago
6 0

Answer: The restaurant would most likely be the best because you get $7.50 and then you get $50 dollers in tips

Step-by-step explanation:

vovangra [49]2 years ago
4 0

Answer:

Aahhahaha

Step-by-step explanation:

your welcome

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9x 2 = 6 what is x?​
evablogger [386]

Answer:

x = \sqrt(6)/3 , - \sqrt(6)/3

Step-by-step explanation:

decimal form:

x= 0.81649658..., -0.81649658...

3 0
3 years ago
I dont understand this
nata0808 [166]

Answer:

The correct answer is:

d) 2x^{2}+3x-3+\frac{3}{4x-6}

Step-by-step explanation:

The given question is regarding polynomial division.

Please find the attached file for the explanation.

Polynomial division gives:

Quotient: 2x^{2}+3x-3

Remainder: 3

8 0
3 years ago
Pythagorean theorem
Talja [164]

Answer:

b=20 yards

Step-by-step explanation:

15^2+x^2=25^2

225+x^2=625

x^2=400

x=20

5 0
3 years ago
John builds a square dog pen that has an area of 81 square feet. He then builds a
Fiesta28 [93]

Answer:

21.0%

Step-by-step explanation:

8 0
3 years ago
Is matrix multiplication comutative?
konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0
3 years ago
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