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hodyreva [135]
3 years ago
12

2 3 5 9 17 _ what is the next number in the sequence

Mathematics
1 answer:
nordsb [41]3 years ago
3 0
The next number is 33
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Of the students at Milton Middle School, 121 are girls. If 55% of the students are girls, how many total students are there at M
Snowcat [4.5K]
The correct answer should be 220
4 0
3 years ago
What is the radius of a circle whose area is 36 π cm squared?
Burka [1]

Answer: 3.39

Step-by-step explanation: maybe

7 0
3 years ago
(3,7)(2,6) Find the equation for the line that falls through the two ordered pairs
Alexxandr [17]

Answer: The equation for the two given points is y=x+b


Step-by-step explanation:

Step 1. First find the slope: 6-7/2-3 = -1/-1=1. The slope is just 1, or x. So for now, the equation is y=x+b

Step 2. We must find the y-intercept, or B. We can plug in any points to find b. Let's use (2, 6) (but you can use (3, 7) too, it doesn't matter) Plug 2 in for x, since 2 represents x, and then do the same for y. ---> 6=2+b.

Step 3. Simplify. 6=2+b. 6-2=2-2+b ---> b=4. Subtract both sides by 2 to get B.

The equation for the two given points is y=x+b

Hope this helps.

7 0
3 years ago
4) The path of a satellite orbiting the earth causes it to pass directly over two
Naily [24]

Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
3 years ago
Plsss hElpp!!!!! TY!!
kari74 [83]

Given:

A circle with diameter 9 cm.

To find:

The area of the circle.

Solution:

The area of a circle is:

A=\pi r^2                   ...(i)

Where r is the radius.

We know that, the diameter of a circle is twice than its radius.

The diameter of the given circle is 9 cm.

r=\dfrac{9}{2}

r=4.5

Substituting r=4.5, \pi =3.14 in (i), we get

A=(3.14)(4.5)^2

A=(3.14)(20.25)

A=63.585

A\approx 63.6

Therefore, the area of the given circle is 63.6.

4 0
3 years ago
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