Answer:
perimeters of the rectangle=p=46.014 metres
Step-by-step explanation:
Given that:
Length (l) = 21 m
Area of rectangle(A) = 42.15 meter-square
Width (w)=?
Required data:
Perimater of Rectangle=p=?
Calculation:
As we know that Area of rectangle=A=l*w
Putting the value we get
42.15 m(square)=(21 m)*w
or w=42.15/21
or w=2.007 m
Now to find perimters of rectangle we know that
p=2(l + w) metres
putting the values
p=2(21+2.007) metres
p=2(23.007) metres
p=46.014 metres
Answer: 0.35
Step-by-step explanation:
35÷100 = 0.35
Answer:
96 cm
53 cm
4,5 Cm
1,5 Cm
1.7dm
0,5m
Step-by-step explanation:
Dm to Cm ×10
mm to cm ÷10
Answer: x = 3.5
Step-by-Step Solution:
Let us first label the figure.
Let the Triangle be ABC with a line DE || BC.
Now, in ∆ABC,
DE || BC (given)
=> AD/DB = AE/EC (by B.P.T)
Substituting the given values,
AD/DB = AE/EC
2/4 = x/7
1/2 = x/7
2x = 7
x = 7/2
=> x = 3.5
Therefore, x = 3.5
