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Vilka [71]
2 years ago
5

Simplify: 8x + 3 +6x-5

Mathematics
2 answers:
Sphinxa [80]2 years ago
6 0

Answer:

14x +2

Step-by-step explanation:

(8x + 6x) +3 -5 = (14x) +3-5

14x (+ 3-5) = 14x (+ 2)

fredd [130]2 years ago
3 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{14x - 2}}}}}

Step-by-step explanation:

\sf{8x + 3 + 6x - 5}

Collect like terms.

Only coefficients of like terms can be added or subtracted

\longrightarrow{ \sf{8x + 6x + 3 - 5}}

\longrightarrow{ \sf{14x + 3 - 5}}

The negative and positive integers are always subtracted but posses the sign of the bigger integer

\longrightarrow{ \sf{14x - 2}}

Hope I helped!

Best regards! :D

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Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30
Dafna11 [192]
Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

\bf u=
\begin{cases}
x=7cos(330^o)\\
\qquad 7\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{7\sqrt{3}}{2}\\
y=7sin(330^o)\\
\qquad 7\cdot -\frac{1}{2}\\
\qquad -\frac{7}{2}
\end{cases}\qquad \qquad v=
\begin{cases}
x=8cos(30^o)\\
\qquad 8\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{8\sqrt{3}}{2}\\
y=8sin(30^o)\\
\qquad 8\cdot \frac{1}{2}\\
\qquad 4
\end{cases}

\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)
\\\\\\
\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~  \stackrel{b}{\frac{1}{2}}\right)\\\\
-------------------------------

\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}
\\\\\\
\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o
8 0
2 years ago
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