Question

PLSSSSSSSS HELLPPPPPP.......Which triangle’s unknown side length measures StartRoot 53 EndRoot units?

Answer 1

The right answer is Option 2: A right triangle with side length of √47 and hypotenuse of 10.

Step-by-step explanation:

We know that;

$a^2 + b^2 = c^2$

We will put the unknown length as √53 to check the solution.

Option 1: a = 6 , b = √53 , c = √91

$(6)^2+(\sqrt{53})^2=(\sqrt{91})^2\\36+53=91\\89\neq 91$

Option 2: a=√47, b = √53, c = 10

$(\sqrt{47})^2+(\sqrt{53})^2=(10)^2\\47+53=100\\100=100$

Option 3: a = √19, b=√53, c= √34

$(\sqrt{19})^2+(\sqrt{53})^2=(\sqrt{34})^2\\19+53=34\\72\neq 34$

Option 4: a=√73, b=√53, c=20

$(\sqrt{73})^2+(\sqrt{53})^2=(20)^2\\73+53=400\\126\neq 400$

Option 2 satisfies pythagoras theorem.

Therefore;

The right answer is Option 2: A right triangle with side length of √47 and hypotenuse of 10.

Keywords: pythagoras theorem, square root

Learn more about pythagoras theorem at:

• brainly.com/question/11203617
• brainly.com/question/11253316

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Answer 2

Answer:

option 2

Step-by-step explanation: