First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
k = 0.0916
Step-by-step explanation:
T(t) =
from question; t = 12 mins , = 50 C , = 80 C , T = 60 C
60 = 50 + (80 - 50)
60-50 = 30
10/30 = (Taking natural Log of both sides)
In(0.3333) = In
-1.0986 = -12k
k = 0.0916
Answer:
Step-by-step explanation:
Area of plane figures
Being r the radius of a circle, the area of a sector defined by an angle is
If a is the repeated side of an isosceles triangle and is the angle they define, then the area of the triangle is
The figure shows a circle with radius of r=7 cm. The white area is equal to the area of the circle minus the blue area
The area of the circle is
The blue area is the sum of the sector defined by the angle (360-150)= and the triangle. An angle of is equivalent to
The area of the sector is
The area of the triangle with center angle 150^o is
The blue area is
Finally, the white area is