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Reil [10]
3 years ago
7

Multiply the binomials (5x + 3) and (2x + 4).

Mathematics
2 answers:
Wewaii [24]3 years ago
8 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{10 {x}^{2}  + 26x + 12}}}}}

Step-by-step explanation:

\sf{(5x + 3)(2x + 4)}

Use distribute property to multiply each term of the first binomial by each term of the second binomial.

\dashrightarrow{ \sf{5x(2x + 4) + 3(2x + 4)}}

\dashrightarrow{ \sf{10 {x}^{2}  + 20x + 6x + 12}}

Collect like terms

\dashrightarrow{ \sf{10 {x}^{2}  + 26x + 12}}

Hope I helped !

Best regards! :D

kati45 [8]3 years ago
5 0

Answer:

HI!

Step-by-step explanation:

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A diner has collected data about customer coffee-drinking habits. They have calculated that P(cream) = 0.5, P(sugar) = 0.6, and
frozen [14]

Answer:

P(cream and sugar) = 0.4

Step-by-step explanation:

* Lets study the meaning of or , and on probability

- The use of the word or means that you are calculating the probability

 that either event A or event B happened

-  Both events do not have to happen

- The use the word and, means that both event A and B have to happen

* The addition rules are:

# P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen

 at the same time)

# P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they

 have at least one outcome in common)

- The union is written as A∪B or “A or B”.

- The intersection is written as A∩B or “A and B”

* Lets solve the question

∵ P(cream) = 0.5

∵ P(sugar) = 0.6

∵ P(cream or sugar) = 0.7

- To find P(cream and sugar) lets use the rule of non-mutually exclusive

∵ P(A or B) = P(A) + P(B) - P(A and B)

∴ P(cream or sugar) = P(cream) + P(sugar) - P(cream and sugar)

- Lets substitute the values of P(cream) , P(sugar) , P(cream or sugar)

 in the rule

∵ 0.7 = 0.5 + 0.6 - P(cream and sugar) ⇒ add the like terms

∴ 0.7 = 1.1 - P(cream and sugar) ⇒ subtract 1.1 from both sides

∴ 0.7 - 1.1 = - P(cream and sugar)

∴ - 0.4 = - P(cream and sugar) ⇒ multiply both sides by -1

∴ 0.4 = P(cream and sugar)

* P(cream and sugar) = 0.4

5 0
3 years ago
Read 2 more answers
In the figure, a || b and m<1 = 35° what is the m<5?​
zlopas [31]

Answer:

Directions: Find the missing measures in each figure. Keep the ... m<B+42 = 90. MLB-48. 8. ... x = 5. X = 14. MCR = 1215)-3 = 57° m<Q = 9614)-3-123°. 16. 21 and 22 form a linear pair. The ... 1. 5. 2. 6. 3. 7. 4. 8 p q. Examples' name the type of angle relationship. ... (4017)+3)+5y+35=180 ... Directions: Find x so that a || b.

Step-by-step explanation:

8 0
3 years ago
Tamara is at the store buying pencils. There is a package with 4 pencils that costs $6 or a package with 5 pencils that costs $7
Mkey [24]

In order to determine the cost of each pencil we have to divide the total cost for the package of pencils by the number of pencils contained

For the 4 pencils box:

Cost per pencil = Total cost/number of pencils

Cost per pencil = 6/4 = 1.5

Similarly, for the 5 pencils package:

Cost per pencil = 7/5 = 1.4

As you can see, the $7 package is better to buy, because each pencil costs $1.4, then, option A is the correct answer

8 0
1 year ago
The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of len
Allisa [31]
First you plug in the data to the formula. So it will be 2(1/3+1/2). You then want to add the fractions together but must first find the common denominator which will be 6. So it is 2(2/6+3/6). The fractions then add up to be 5/6. So all you have to do is multiply it by 2 to get 5/3 which simplifies to 1 2/3 so it is D. 
4 0
3 years ago
Read 2 more answers
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
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