The equation of a line that passes throug the point (x1,y1) and has a sloppe of m is
y-y1=m(x-x1)
the slope of paralell lines ar the same
y=3x+2
y=mx+b
m=slope
m=3
a point is (-2,0)
slope is 3
y-0=3(x-(-2))
y=3(x+2)
y=3x+6
the equation is y=3x+6
F'(x) = 7sec x . tan x - 5.
Answer:

Step-by-step explanation:

270 x 0.75 = 202.5 students, so say 203 students