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ICE Princess25 [194]
3 years ago
14

find the area of a triangle if its two sides measure 6 inches and 9 inches and the bisector of the angle between the sides is 4

square root of 3

Mathematics
1 answer:
irga5000 [103]3 years ago
4 0
Look at the attached file

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Find the gradient of the tangent to the curve y = 5x³ + 3x² - x + 4​
Luba_88 [7]

The gradient of the tangent to the curve y = 5x³ + 3x² - x + 4​ is 15x²+6x-1.

<h3>What is the gradient?</h3>

A differential operator is used for a function having a vector value in three dimensions to produce a vector whose three components are the partial derivatives of the function with respect to its three variables.

The given equation for the curve is;

y = 5x³ + 3x² - x + 4​

The gradient of the tangent to the curve is;

\rm y'=\frac{dy}{dx} \\\\ y'= 5x^3 + 3x^2- x + 4 \\\\\ y'=15x^2+6x-1

Hence,the gradient of the tangent to the curve y = 5x³ + 3x² - x + 4​ is 15x²+6x-1.

To learn more about the gradient refer to;

brainly.com/question/13020257

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7 0
2 years ago
Consider the equation below. (If an answer does not exist, enter DNE.) f(x) = x3 − 6x2 − 15x + 2 (a) Find the interval on which
Burka [1]

Answer:

a) (-\infty, -1) \cup (5, \infty)

b) (-1,5)

Step-by-step explanation:

The first step to solve this question is finding the roots of the derivative of x.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(x) = x^{3} - 6x^{2} - 15x + 2

So

f'(x) = 3x^{2} - 12x - 15

Finding the roots:

3x^{2} - 12x - 15 = 0

Simplifying by -3

x^{2} - 4x - 5 = 0

So a = 1, b = -4, c = -5

Then

\bigtriangleup = (-4)^{2} - 4*1*(-5) = 36

x_{1} = \frac{-(-4) + \sqrt{36}}{2} = 5

x_{2} = \frac{-(-4) - \sqrt{36}}{2} = -1

So the function can be divided in three intervals.

They are:

Less than -1

Between -1 and 5

Higher than 5

In which it increases and which it decreases?

Less than -1

Lets find the derivative in a point in this interval, for example, -2

f'(x) = 3x^{2} - 12x - 15

f'(-2) = 3*(-2)^{2} - 12*(-2) - 15 = 21

Positive.

So in the interval of (-\infty, -1), the function increases.

Between -1 and 5

Will choose 0.

f'(x) = 3x^{2} - 12x - 15

f'(0) = 3*(0)^{2} - 12*(0) - 15 = -15

Negative.

So in the interval of (-1,5), the function decreases.

Higher than 5

Will choose 6.

f'(x) = 3x^{2} - 12x - 15

f'(6) = 3*(6)^{2} - 12*(6) - 15 = 21

Positive

So in the interval of (5, \infty), the function increases.

(a) Find the interval on which f is increasing.

Using interval notation

(-\infty, -1) \cup (5, \infty)

b) Find the interval on which f is decreasing.

(-1,5)

5 0
3 years ago
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