The answer to the problem "Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius" is A = (160/3 π + 16 √3) inches². Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.
Answer:
<h2>The son is 10 Mary is 28</h2>
Step-by-step explanation:
I hope dis helps
Answer:
<em>Answer is option d</em><em> </em>
<em>Answer is </em><em>given below with explanations</em><em>. </em>
Step-by-step explanation:
We can prove that the two triangles are similar.
We can prove this using AA criterion of similarity.
In triangle DNC and triangle QSC
Vertically opposite angles are equal.
Then Angle QCS = Angle DCN
Two parallel lines cut by a transversal line make the alternate angles are equal.
Then Angle NDC = Angle CQS
By AA criterion of similarity
TRIANGLE DNC ~ TRIANGLE QSC
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>
It should be (2x-3)x(3x+2)
