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valentina_108 [34]
3 years ago
14

Can someone help me with question 11

Mathematics
1 answer:
matrenka [14]3 years ago
7 0
The full answer is 1.04, but the nearest hundredth would be 1.00
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PLEASE HELP FAST Its in the photo below
azamat

Answer:

there’s no photo

Step-by-step explanation:

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does the pythagorean theorem hold for shapes other than squares constructed on the legs and hypotenuse of a right triagles
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It is 7 thousand and a bunch of random numbers

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What is the value of z?<br><br> Enter your answer in the box.
Georgia [21]

Answer:

23

Step-by-step explanation:

Because the angles of a triangle always add up to 180°, you can set up an equation like this.

62+95+z=180

157+z=180

157-157+z=180-157

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A textbook store sold a combined total of 290 math and history textbooks in a week. The number of math textbooks sold was 64 mor
11Alexandr11 [23.1K]

Answer:

113

Step-by-step explanation:

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2 years ago
A rock is launched from a cannon. After 1 second, the rock is 58 feet in the air; after 2 seconds, it is 112 feet in the air. Us
max2010maxim [7]

Answer:

Step-by-step explanation: This is the quadratic function:

h(x)=ax²+bx+c

We have two points:

(1,58)

(2,112)

Now, we calculate this quadratic funtion.

we assume that h(0)=0

Therefore:

a(0)²+b(0)+c=0

c=0

(1,58)

a(1)²+b(1)=58

a+b=58  (1)

(2,112)

a(2)²+b(2)=112

4a+2b=112

2a+b=56  (1)

With the equations (1) and (2) we make a system of equations:

a+b=58

2a+b=56

we can solve this system of equations by reduction method.

-(a+b=58)

2a+b=56

---------------------

a=-2

-2(a+b=58)

2a+b=56

-------------------

      -b=-60  ⇒  b=60

The function is:

h(x)=ax²+bx+c

h(x)=-2x²+60x

Now find the height, in feet, of the rock after 10 seconds in the air.

h(10)=-2(10)²+60(10)

h(10)=-200+600=400

Answer: 400 ft.

8 0
2 years ago
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