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2 years ago

I need help with this question please.

Mathematics

1 answer:

Reil [10]2 years ago

7 0

Answer:

10 n equals 6

Step-by-step explanation:

Why? Because that has nothing to do with the problem and no solution for 3/5.

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Two figures are similar, and the scale factor is 2/3

d1i1m1o1n [39]

Answer:

The answer is 8.

Step-by-step explanation:

The scale factor between the figures is 2/3, this means that the ratio of the smaller figure to the larger figure is 2/3:

$\frac{smaller\:figure}{larger\:figure}=\frac{2}{3}$ .

So when a side of the the larger figure is 12 then:

$\frac{smaller\:figure\: side}{12}=\frac{2}{3}$

Therefore

$smaller\:figure\:side=\frac{2}{3}*12=8$ .

Thus the length of the corresponding smaller side is 8.

3 0

3 years ago

Read 2 more answers

Answer choice <br> D) A worker with 15 years of service gets 5 weeks of vacation and each year.

otez555 [7]

Answer: it seems to be D, but the equation makes practically no sense!

The value of the factor changes for the different amounts of service years and vacation weeks.

Step-by-step explanation: The equation means that the employee is trying to figure out the value of the "v-factor" for how vacation time is earned.

If you substitute the number of service years into the left side of the "formula" and vacation weeks on the right side, then solve for "v", v(15)=5 you get v= 1/3 or 0.33

If you substitute other numbers, like v(2)=2, so v= 1 then v(30) = 8, v = 4/15 or 0.2667. You see the factor's value decreases. The company is much more generous to to employees with one or two years of service than with the older ones.

7 0

3 years ago

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below

mafiozo [28]

Answer:

a) $\bar X = 369.62$

b) $Median=175$

c) $Mode =450$

With a frequency of 4

d) $MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

<u>e)</u> $s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

Replacing we got:

$\bar X = 369.62$

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

$Median=175$

Part c

The mode is the most repeated value in the sample and for this case is:

$Mode =450$

With a frequency of 4

Part d

The midrange for this case is defined as:

$MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5$

Part e

For this case we can calculate the deviation given by:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$s = 621.76$

And we can find the limits without any outliers using two deviations from the mean and we got:

$\bar X+2\sigma = 369.62 +2*621.76 = 1361$

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0

3 years ago

Math question down below

dangina [55]

Answer:

Step-by-step explanation:

10.98/2=5.49

16.19/3=5.40

21.15/4=5.29

26.85/5=5.37

4 0

3 years ago

The temperature one morning in Shasta was LaTeX: -12^\circ F− 12 ∘ F. By the afternoon, the temperature had risen LaTeX: 8^\circ

Vlad [161]

Answer:

The Temperature in the afternoon was $-4\° F$ .

Step-by-step explanation:

Given:

Temperature in the morning = $-12\° F$

Rise in temperature = $8\° F$

We need to find the temperature in the afternoon.

Solution:

Now we know that;

temperature in the afternoon is equal to Temperature in the morning plus Rise in temperature in afternoon.

framing in equation form we get;

temperature in the afternoon = $-12\° F+8\° F=-4\° F$

Hence the Temperature in the afternoon was $-4\° F$ .

3 0

3 years ago