Area of a rectangle is length x width.
Let the width = x
The length would be x +7. ( 7 inches longer than the width)
Area = 20
Set up the formula:
20 = x * x+7
Simplify the right side:
20 = x^2 + 7x
Subtract 29 from both sides:
X^2 + 7x -20 = 0
Solve using the quadratic equation
X = -b + sqrt(b^2 -4ac) / 2a
X = -7 + sqrt(7^2-4(1)(-20) / 2(1) (exact answer)
X = 2.178908 ( as a decimal)
The width is 2.178907 inches (round as needed)
The length would be 9.178907 inches ( round as needed.)
Depending on how you round, when you multiply them together you get approximately 20 square inches.
The answer is 4 bc 4a+8b+4c=1. 4a*4=16a 8b*4=32b and 4c*4=16c so 1*4=4. since ur finding four times as much of the first problem then 16a+16c+32b=4
Answer:
T'(2, - 5 )
Step-by-step explanation:
Under a rotation about the origin of 180°
a point (x, y ) → (- x, - y ), thus
T(- 2, 5 ) → T'(2, - 5 )
Correct option is C. The value of 2x = 10
Given that
10 + x is 5 more than 10
Formally, we can express this
10 + x = 10 + 5
⇒x = 15 − 10
⇒x = 5
To find 2x,
2x = 2 × x
= 2 × 5
= 10
Therefore, the value of ′ 2x ′ is ′ 10 ′
To learn more about linear equation from given link
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Answer: Domain of the given function is all real numbers.
Range of the given function is {y | y>=1}
Step-by-step explanation:
The given function is a polynomial and the domain of any polynomial is all the real numbers because for any value of x, the function will have some value.
Hence, the domain will be all real numbers.
Range is the set of y values for which the function is defined.
This is a polynomial and to find the range, we will simplify the polynomial.
Therefore, for any value of x, f(x) ≥ 1
Hence, the range becomes {y | y ≥ 1}
