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DiKsa [7]
3 years ago
8

Brainliest question Please help me now plz

Mathematics
1 answer:
V125BC [204]3 years ago
6 0
Side a = 10.98991
Side b = 11.69522
Side c = 4

Angle ∠A = 70° = 1.22173 rad = 7/18π
Angle ∠B = 90° = 1.5708 rad = π/2
Angle ∠C = 20° = 0.34907 rad = π/9


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<img src="https://tex.z-dn.net/?f=7%5Csqrt%7B3%7D%20%2B%5Csqrt%7B63" id="TexFormula1" title="7\sqrt{3} +\sqrt{63" alt="7\sqrt{3}
mezya [45]

Answer:7√3 + 3√7

Step-by-step explanation:

7√3 + √63

=> 7√3 + √(7×9)

=> 7√3 + (√7 × √9)

=> 7√3 + 3√7

8 0
3 years ago
Let X be a positive continuous random variable with density fXpxq. Let Y " lnpXq. (a) Find the density fY pyq of Y in terms of t
salantis [7]

Answer:

X density = fXpxq and

Y" =InpXq

Now to find Y density FYpyq interms of the density of X we compare the density of X with Y"

fX = In

And PXq =pxq

Thus replacing x with y,

PXq = pyq

(a) Hence the density of Y is FYpyq

(b) at p0, fYpyq =fYp0q= 0

At 5s, FYpyq =5

7 0
3 years ago
Read 2 more answers
The Fibonacci sequence is defined by $F_1 = F_2 = 1$ and $F_{n + 2} = F_{n + 1} + F_n$. Find the remainder when $F_{1999}$ is di
zavuch27 [327]

Answer:

The remainder is 1

Step-by-step explanation:

Given the Fibonacci sequence

F_1 = F_2 = 1, and

F_(n + 2) = F_(n + 1) + F_n

We want to find the remainder when F_(1999) is divided by 5.

Let us write the first 20 numbers of the sequence in (mod 5). They are

F_1 = 1,

F_2 = 1,

F_3 = 2,

F_4 = 3,

F_5 = 5 = 0 (mod 5),

F_6 = 3,

F_7 = 3,

F_8 = 1

F_(9) = 4

F_(10) = 0

F_(11) = 4

F_(12) = 4

F_(13) = 3

F_(14) = 2

F_(15) = 0

F_(16) = 2

F_(17) = 2

F_(18) = 4

F_(19) = 1

F_(20) = 0

We have: 1, 1, 2, 3, 0, 3, 3, 1, 4, 0, 4, 4, 3, 2, 0, 2, 2, 4, 1, 0

Now, 1999 = 19(mod 20)

The 19th number in the sequence is 1.

So, the remainder is 1.

6 0
3 years ago
Help plz!! Will give brainliest
r-ruslan [8.4K]

Answer:

C is the sorrect because those both lines are equal

Step-by-step explanation:

6 0
3 years ago
The grade appeal process at a university requires that a jury be structured by selecting six individuals randomly from a pool of
romanna [79]

Answer: a) \dfrac{3}{874}

b) \dfrac{30}{3059}

c) \dfrac{3575}{12236}

Step-by-step explanation:

Given : Number of students : 11

Number of faculty members : 13

Total persons : 11+13=24

Total number of ways to structure a jury of six people from a group of 24 people :-

^{24}C_{6}=\dfrac{24!}{6!(24-6)!}=134596

a) Number of ways of selecting a jury of all​ students :-

^{11}C_{6}=\dfrac{11!}{6!(11-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{462}{134596}=\dfrac{3}{874}

b) Number of ways of selecting a jury of all​ faculty :-

^{13}C_{6}=\dfrac{13!}{6!(13-6)!}=462

Then , the probability of selecting a jury of all​ students :-

\dfrac{1716}{134596}=\dfrac{30}{3059}

c) Number of ways of selecting a jury of two students and four ​faculty :-

^{11}C_{2}\times^{13}C_{4}=\dfrac{11!}{2!(11-2)!}\times\dfrac{13!}{4!(13-4)!}=39325

Then , the probability of selecting a jury of all​ students :-

\dfrac{39325}{134596}=\dfrac{3575}{12236}

3 0
3 years ago
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