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Bas_tet [7]
3 years ago
10

What is the equation in point-slope form of a line that passes through the points (7,-8) and (-4,6)? HURRY!!!!!!​

Mathematics
1 answer:
erastova [34]3 years ago
5 0

Answer:

y - 7 = \frac{14}{-11}(x + 8)

Step-by-step explanation:

Use the slope formula \frac{y2 - y1}{x2-x1} to work out the slope

Then pick one point to insert into the formula y - y1 = m(x - x1)

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To determine whether or not they have a certain disease, 150 people are to have their blood tested. However, rather than testing
Sophie [7]

Answer:

The answer is 75 tests for 150 people.

Step-by-step explanation:

Firstly, with 150 people, we can divide into 15 groups; and the probability of disease is 0.04, there are 6 persons who possibly get disease.

Therefor, the maximum number of groups with an individual getting disease is 6. Then, 6 * 11 tests = 66 tests required.

15 groups - 6 groups with disease = 9 groups of negative with 9 tests.

In conclusion, there are 75 tests required.  

 

7 0
3 years ago
Write the point-slope form of the equation of the line with a slope of - 2 and an x-intercept of - 1. Include your work in your
coldgirl [10]
X-intercept is -1 implies line passes through (-1,0). 
So point slope form is

y - 0 = -2 (x -(-1) )

>> y  = -2 (x +1)   <----- FINAL ANSWER
8 0
3 years ago
Read 2 more answers
What is a reminder of 46 divided by 2
Tema [17]
The answer two your problem is no remainder again because 46 divided by 2 equals 23
3 0
3 years ago
Read 2 more answers
Write the expression 12^-2 in simplest form.
olga2289 [7]

Answer:

Step-by-step explanation:

1/12^2 = 1/144

8 0
2 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
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