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3 years ago

7

PLZ HELP. i dont have a lot of time and i dont understand this problem. the question is on the picture. plz explain

1 answer:

r-ruslan [8.4K]3 years ago

5 0

@HOTSAUCE75 do you know? i think its 35,280

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How do you solve for x? -12+7=-5(x+2)

dusya [7]

-5= -5x-10

Plus 10 from both sides

5=-5x
X = -1

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Find the percent: 80% of 8

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Answer:

6.4

Step-by-step explanation:

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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

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3 years ago

Wes has been tracking the population of a town. The population was 3,460 last year and has been increasing by 1.35 times each ye

AveGali [126]

After x years the population of a town is 3460*[(1.35)^x]

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Multiple choice math question.

Marrrta [24]

Y=x. I hope that this helped! Good luck! :)

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