Answer:
def print_popcorn_time(bag_ounces):
if bag_ounces<3:
print("Too Small")
elif bag_ounces>10:
print("Too Large")
else:
total = 6*bag_ounces
print('{} seconds'.format(total))
Explanation:
Using Python programming language
The function is defined to accept a single parameter
Using a combination of if/elif/else statements, the approprite message is displayed when the function is called
Why is cloud better than on-premise? Dubbed better than on-premise due to its flexibility, reliability and security, cloud removes the hassle of maintaining and updating systems, allowing you to invest your time, money and resources into fulfilling your core business strategies.
The security of the cloud vs. on-premises is a key consideration in this debate. Cloud security controls have historically been considered less robust than onprem ones, but cloud computing is no longer a new technology. . A company running its own on-premises servers retains more complete control over security.
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Answer:
It 5
Explain
number 28 is A and number 29 is 5
When this case would appear, one thing that I would do personally would first, go to the settings, in then, after having this done, I would then "scroll down" to where ti would say "restore (uefi/bios) files, and from there, you would get every value that would would have from the beginning in your chip.
And also, what is truly unique would be the fact that you would be able to choose the "restore point" that you would like for it to appear.
Answer:
Explanation:
Following are the Semaphores:
Customers: Counts waiting customers;
Barbers: Number of idle barbers (0 or 1)
mutex: Used for mutual exclusion.
Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves
Shared data variable:
count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.
// shared data
semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;
int count_cust= 0;
void barber() {
while(true) { //shop is always open
wait(customers); //sleep when there are no waiting customers
wait(mutex); //mutex for accessing customers1
count_cust= count_cust-1; //customer left
signal(barbers);
signal(mutex);
cut_hair();
}
}
void customer() {
wait(mutex); //mutex for accessing count_cust
if (count_cust< n) {
count_cust= count_cust+1; //new customer
signal(customers); signal(mutex);
wait(barbers); //wait for available barbers get_haircut();
}
else { //do nothing (leave) when all chairs are used. signal(mutex);
}
}
cut_hair(){ waiting(cutting);
}
get_haircut(){
get hair cut for some time; signal(cutting);
}
