To calculate the inverse isolate x on one side and switch x with y on both sides
1)
y=(2x-3)/5
5y=2x-3
5y+3=2x
(5y+3)/2=x
-> f(x)=(5x+3)/2
2)
y=(x+8)/2
2y=x+8
2y-8=x
-> f(x)=2x-8
3)
y=(x+2)/7
7y=x+2
7y-2=x
-> f(x)=7x-2
4)
y=(1-2x)/x
y=(1/x)-2
y+2=1/x
x=1/(y+2)
-> f(x)=1/(x+2)
Answer:490pi
Step-by-step explanation:just trust me
Answer and Step-by-step explanation:
Given that probability of you winning each game = 0.68
And probability of you winning next game = 0.81
Your friend's chance of winning/you losing would be = 1-0.68= 0.32
also his chance of winning next game = 0.73
To find probability that you would win the series given that you need to win two games to win the series
= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game
= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81
=0.8750
Therefore probability that you would win the series = 0.8750
Note: here we found the probability of winning by adding(or) up the three possible combinations that would result in a win
