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3 years ago

Help me PLEASEEEE im giving out brainly to the earliest and best one :D

Mathematics

1 answer:

Vinil7 [7]3 years ago

7 0

Y= 5x

Y= 5(2x ) = 10x

Y= 10x/ 5x

= 2

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I need help on both of these please///:(

SCORPION-xisa [38]

14. The distance between the two points is 14.866.

Distance can be calculated with the following formula:

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(12-2)²+(5-(-6))²

d=√10²+11²

d=√100+121

d=√221

d=14.866

15. The distance between the two points is 20.248.

Use the same formula to find the distance.

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(4-(-3))²+(12-(-7))²

d=√7²+19²

d=√49+361

d=√410

d=20.248

4 0

3 years ago

What is the solution of the equation when solved using the quadratic formula?<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B

Artemon [7]

Answer:

$x=\pm2i\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define Equation

x² + 20 = 0

Step 2: Identify Variables

a = 1

b = 0

c = 20

Step 3: Find roots x

Substitute: $x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}$
Exponents: $x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}$
Multiply: $x=\frac{-0\pm\sqrt{0-80} }{2}$
Subtract: $x=\frac{\pm\sqrt{-80} }{2}$
Factor: $x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}$
Simplify: $x=\frac{\pm4i\sqrt{5} }{2}$
Divide: $x=\pm2i\sqrt{5}$

6 0

3 years ago

A line passes through the points (7, 10) and (7,20). Which statement is true about the line?

wariber [46]

Answer:The answer is It has no slope because x2 - x1 in the formula m=y2-y1-x2-x1 is zero, and the denominator of a fraction cannot be zero

Step-by-step explanation:

I did the quiz

7 0

3 years ago

The receipt shows the prices of goods that Robert bought at the store.

Vladimir79 [104]

Answer:

Step-by-step explanation : by subtracting the 8 by 4

5 0

3 years ago

the function intersects its midline at (-pi,-8) and has a maximum point at (pi/4,-1.5) write an equation

Tcecarenko [31]

The equation that represents the sinusoidal function is $x(t) = -8 + 6.5 \cdot \sin \left[\left(\frac{2}{3} \pm \frac{4\cdot i}{3}\right)\cdot t + \left(\frac{2\pi}{3} \pm \frac{7\pi \cdot i}{3} \right)\right]$ , $i\in \mathbb{Z}$ .

<h3>Procedure - Determination of an appropriate function based on given information</h3>

In this question we must find an appropriate model for a periodic function based on the information from statement. Sinusoidal functions are the most typical functions which intersects a midline ( $x_{mid}$ ) and has both a maximum ( $x_{max}$ ) and a minimum ( $x_{min}$ ).

Sinusoidal functions have in most cases the following form:

$x(t) = x_{mid} + \left(\frac{x_{max}-x_{min}}{2} \right)\cdot \sin (\omega \cdot t + \phi)$ (1)

Where:

$\omega$ - Angular frequency
$\phi$ - Angular phase, in radians.

If we know that $x_{min} = -14.5$ , $x_{mid} = -8$ , $x_{max} = -1.5$ , $(t, x) = (-\pi, -8)$ and $(t, x) = \left(\frac{\pi}{4}, -1.5 \right)$ , then the sinusoidal function is: