This math problem is about rounding. So you need to round the probability of it for example there is a big probability that it will land on red again.
17 * 0 + -2.
Now we rewrite the equation and make it 17 * 0 - 2 and u get -2.
Approximately 65% of the distribution lies within one standard deviation of the mean, which is to say,
P(72 ≤ x ≤ 86) ≈ 0.65
Normal distributions are symmetric, so the percentage of values one standard deviation below the mean is equal to the percentage of values one standard deviation above the mean.
P(72 ≤ x ≤ 79) = P(79 ≤ x ≤ 86)
but since the sum of these make up P(72 ≤ x ≤ 86), we find
P(72 ≤ x ≤ 79) ≈ 0.65/2 = 0.325
Also due to symmetry, exactly half of the distribution lies to either side of the mean; namely,
P(x ≥ 79) = 0.5
It follows that
P(x ≥ 72) = P(72 ≤ x ≤ 79) + P(79 ≤ x)
P(x ≥ 72) = 0.325 + 0.5
P(x ≥ 72) = 0.825 ≈ 0.84
Answer:
The values for expression is h = - 2 and k = 5
Step-by-step explanation:
Given algebraic expression can be written as :
2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k
Now opening the bracket
Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3 ) + k
Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12 +k
Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12 + k
Now, equating the equation both sides
I.e - 10 = ( h - 2 )
Or , h - 2 = - 10
I.e , h = - 10 + 2
∴ h = - 2
Again , 11 = ( 3 - 4 h )
or, 11 = 3 - 4 h
or, 11 - 3 = - 4 h
or, 8 = - 4 h
∴ h = 
I.e h = - 2
Again
- 7 = - 12 + k
Or, k = - 7 + 12
∴ k = 5
Hence The values for expression is h = - 2 and k = 5 . Answer