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victus00 [196]
2 years ago
8

What is the solution of the equation when solved using the quadratic formula?

20%3D0" id="TexFormula1" title="x^{2} +20=0" alt="x^{2} +20=0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Artemon [7]2 years ago
6 0

Answer:

x=\pm2i\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Numbers: √-1  = i

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x² + 20 = 0

<u>Step 2: Identify Variables</u>

a = 1

b = 0

c = 20

<u>Step 3: Find roots </u><em><u>x</u></em>

  1. Substitute:                    x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}
  2. Exponents:                   x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}
  3. Multiply:                        x=\frac{-0\pm\sqrt{0-80} }{2}
  4. Subtract:                       x=\frac{\pm\sqrt{-80} }{2}
  5. Factor:                          x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}
  6. Simplify:                        x=\frac{\pm4i\sqrt{5} }{2}
  7. Divide:                          x=\pm2i\sqrt{5}
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