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Simora [160]
3 years ago
12

I NEED HELP ASAP! Alex wants to buy carpet to cover his whole living room, except for the tiled floor. The tiled floor is 5 3/4

FT by 3 1/2 FT. WHATS THE AREA OF THE CARPET IT NEEDS TO COVER?

Mathematics
1 answer:
docker41 [41]3 years ago
7 0

Answer:

53.375 or 427/8 or 53 3/8

Step-by-step explanation:

To solve this you must find the area of both the carpet and the tiled floor. You use the equation area = length x width

Carpet: 10.5 x 7 = 73.5

Tile: 5.75 x 3.5 = 20.125

The you subtract the area of the tiled floor from the carpet

73.5 - 20.125 = 53.375

(I prefer to work in decimals but most of the time they want fraction answers so 53.375 = 427/8 = 53 3/8

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The minute hand of a clock is 4 inches long. How far does the tip of the minute hand move in 35 minutes? If necessary, round the
blsea [12.9K]

Answer:

14.66 inches

Step-by-step explanation:

Calculation for How far does the tip of the minute hand move in 35 minutes

The tip of a minute hand will always travels at 360 degrees in an hour ( 60 minutes)

Hence, the tip of the minute hand

distance will be calculated using this formula

Circumference of a circle=2*π*Radius* Clock Tip hand movement/Number of minutes per hour

Let plug in the formula

Circumference of a circle==2*π*4 inches*35 minutes/60 minutes

Circumference of a circle= =2*π*4 inches*0.58333

Circumference of a circle==14.659 inches

Circumference of a circle==14.66 inches (Approximately)

Therefore How far does the tip of the minute hand move in 35 minutes will be 14.58 inches

8 0
3 years ago
Q 2 PLEASE HELP ME FIGURE THIS OUT
suter [353]

Answer: IV, positive, \frac{\pi} {6}, - sec \frac{\pi} {6}, \frac{2\sqrt{3}}{3}

<u>Step-by-step explanation:</u>

a) Look at the Unit Circle to see that \frac{11\pi} {6} = 330°, which is located in Quadrant IV.

b) The coordinate (cos θ, sin θ) for \frac{11\pi} {6} is: (\frac{\sqrt{3}} {2},\frac{-1}{2})

sec = \frac{1}{cos} = \frac{2}{\sqrt{3}} which is positive

c) Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the given angle \frac{11\pi} {6} from 2π: \frac{12\pi} {6} - \frac{11\pi} {6} = \frac{\pi} {6}

d) the reference angle is below the x-axis so the given angle is equal to the negative of the reference angle: - sec \frac{\pi} {6}.

e) sec \frac{11\pi} {6} = \frac{2}{\sqrt{3}} = \frac{2}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}} = \frac{2\sqrt{3}}{3}

***************************************************************************************

Answer: \frac{18\pi}{11}, IV, \frac{4\pi} {11}

<u>Step-by-step explanation:</u>

2π is one rotation.  2π = \frac{22\pi}{11}

\frac{-26\pi}{11} + \frac{22\pi}{11} = \frac{-4\pi}{11}

\frac{-4\pi}{11} + \frac{22\pi}{11} = \frac{18\pi}{11}

Convert the radians into degrees to see which Quadrant it is in by setting up the proportion and cross multiplying:

\frac{\pi}{180}= \frac{18\pi}{11x}

π(11x) = (180)18π

x = \frac{180(18\pi}{11\pi}

x = 295°     <em>which lies in Quadrant IV</em>

Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the angle of least nonegative value\frac{18\pi} {11} from 2π: \frac{22\pi} {11} - \frac{18\pi} {11} = \frac{4\pi} {11}

***************************************************************************************

Answer: \frac{5\pi}{3}, IV, \frac{4\pi} {11}, \frac{\pi} {3}

<u>Step-by-step explanation:</u>

2π is one rotation.  2π = \frac{6\pi}{3}

\frac{-13\pi}{3} + \frac{6\pi}{3} = \frac{-7\pi}{3}

\frac{-7\pi}{3} + \frac{6\pi}{3} = \frac{-\pi}{3}

\frac{-\pi}{3} + \frac{6\pi}{3} = \frac{5\pi}{3}

This is on the Unit Circle at 300°, which is located in Quadrant IV

Since the given angle is in Quadrant IV, which is closest to the x-axis at 360° = 2π, the reference angle can be found by subtracting the angle of least nonegative value\frac{5\pi} {3} from 2π: \frac{6\pi} {3} - \frac{5\pi} {3} = \frac{\pi} {3}


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Musa age is twothird of abus age if the sum lf their ages equals to 30 what is abu age​
Amanda [17]

Answer:

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Y=x^2-4x-1 in vertex form
belka [17]
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Solutions

=11+5+3x^2+8x^1&#10;&#10;=11+5+3x^2+8x
<span><span><span>
</span></span></span>Combine Like Terms:

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<span><span>
</span></span>Simplify=3x^2+8x+16
4 0
3 years ago
Read 2 more answers
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