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lara31 [8.8K]
3 years ago
6

Helppp!!!! please!!!

Mathematics
2 answers:
lianna [129]3 years ago
7 0

Answer:

HEY MATE YOUR ANSWER IS

1A

2C

3B

<h2>HOPE IT HELPS YOU </h2>
ch4aika [34]3 years ago
3 0

1 looks like it's going to be C but dont depend on it yet,

2 looks like A, I might be wrong sense it's been awhile.

didnt see 3 but it looks to be B.

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Which expressions are a factor of -48xyz – 24xy + 40xyz?
11Alexandr11 [23.1K]
The answer to your question is D B and G.
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3 years ago
I WILL GIVE BRAINLIEST IF U CAN HELP ME WITH ANY OF MY QUESTIONS!!!
faltersainse [42]

Answer:

12.5

Step-by-step explanation:

square root of 10^2 - 8^2 = 6 gives us missing side

sin^-1(8/10) = 53.13 gives us half of the angle

90-53.13 = 36.869 gives us the angle of the triangle on the right

tan(36.869) x 6 = 4.5

4.5 + 8 = 12.5

Hope that helps,

Good Luck! x

3 0
3 years ago
Mrs. Wang is 23 years older than her daughter. In 5 years, their age will total 63. How old are they now?
ella [17]
Daughter is 35 and mother is 58
5 0
3 years ago
Read 2 more answers
Please solve this it’s about math
sineoko [7]
#3 - [D = (6 - 2)^2 + (4 - 1)^2] []     >>  D= [Square root of} 16+9

So the awnser to #3 is - 5
3 0
3 years ago
Can someone please answer these questions to help me understand? Please and thank you! Will mark as brainliest!!
Nadya [2.5K]

QUESTION 1  

If a function is continuous at x=a, then \lim_{x \to a}f(x)=f(a)  

Let us find the limit first,  

\lim_{x \to 4} \frac{x-4}{x+5}  

As x \rightarrow 4, x-4 \rightarrow 0,x+5 \rightarrow 9 and f(x) \rightarrow \frac{0}{9}=0  

\therefore \lim_{x \to 4} \frac{x-4}{x+5}=0  

Let us now find the functional value at x=4  

f(4)=\frac{4-4}{4+5} =\frac{0}{9}=0  

Since  

\lim_{x \to 4} f(x)=\frac{x-4}{x+5}=f(4), the function is continuous at a=4.  

QUESTION 2  

The correct answer is table 2. See attachment.


In this table the values of x approaches zero from both sides.


This can help us determine if the one sided limits are approaching the same value.

As we are getting closer and closer to zero from both sides, the function is approaching 2.


The values are also very close to zero unlike those in table 4.


The correct answer is B


QUESTION 3


We want to evaluate;


\lim_{x \to 1} \frac{x^3+5x^2+3x-9}{x-1}


using the properties of limits.


A direct evaluation gives \frac{1^3+5(1)^2+3(1)-9}{1-1}=\frac{0}{0}.


This indeterminate form suggests that, we simplify the function first.


We factor to obtain,


\lim_{x \to 1} \frac{(x-1)(x+3)^2}{x-1}


We cancel common factors to get,


\lim_{x \to 1} (x+3)^2


=(1+3)^2=16


The correct answer is D



QUESTION 4

We can see from the table that as x approaches -2 from both sides, the function approaches -4


Hence the limit is -4.


See attachment


The correct answer is option A

3 0
3 years ago
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