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3 years ago

14

sarah simplify each of the Expressions what is the difference between the values of the two expressions 3 * 12 - 9 + 10 * 3 (12

- 9 )+ 10

1 answer:

mylen [45]3 years ago

7 0

I don’t really knowwwwwww

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new mexicos land area is about 0.03 of the total area of the united states. what percent is new mexicos land area of total area

gizmo_the_mogwai [7]

If you would like to know what percent is New Mexico's land area of total area of the United States, you can do this using the following step:

0.03 = 3/100 = 3%

The correct result would be 3%.

8 0

4 years ago

What is $8.15 divided by 26 equal<br> Can I have the exact quotient<br> Please

KIM [24]

If you are asking for the rounded amount, it would be about 3.19
hope i understood the question and i helped a bit !

8 0

4 years ago

Caroline's gross annual salary is $47,448 What is the max amount of rent she can afford to pay?

morpeh [17]

47,448/12=$3954

As, 28/36 rule states that maximum of 28% of your monthly expenditure should be spent on housing finances.

0.28*3954=$1107,12

Answer: $1107.

4 0

3 years ago

There’s a prime number less than 20 in numerical order

vivado [14]

Answer:

False

Step-by-step explanation:

All prime numbers between 1 and 20 are:

2, 3, 5, 7, 11, 13, 17, and 19.

None of these are in numerical order like 67.

3 0

4 years ago

Read 2 more answers

Use a triple integral to find the volume of the tetrahedron T bounded by the planes x+2y+z=2, x=2y, x=0 and z=0

Tanzania [10]

Answer:

Volume of the Tetrahedron T = $\frac{1}{3}$

Step-by-step explanation:

As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0

We have,

z = 0 and x + 2y + z = 2

⇒ z = 2 - x - 2y

∴ The limits of z are :

0 ≤ z ≤ 2 - x - 2y

Now, in the xy- plane , the equations becomes

x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)

Firstly , we find the intersection between the lines x = 2y and x + 2y = 2

∴ we get

2y + 2y = 2

⇒4y = 2

⇒y = $\frac{2}{4} = \frac{1}{2}$ = 0.5

⇒x = 2( $\frac{1}{2}$ ) = 1

So, the intersection point is ( 1, 0.5)

As we have x = 0 and x = 1

∴ The limits of x are :

0 ≤ x ≤ 1

Also,

x = 2y

⇒y = $\frac{x}{2}$

and x + 2y = 2

⇒2y = 2 - x

⇒y = 1 - $\frac{x}{2}$

∴ The limits of y are :

$\frac{x}{2}$ ≤ y ≤ 1 - $\frac{x}{2}$

So, we get

Volume = $\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}\int\limits^{2-x-2y}_{z=0} {dz} \, dy \, dx$

= $\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \, \, dy \, dx$

= $\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{(2-x-2y)} \, \, dy \, dx$

= $\int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx$

= $\int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2}) -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2} + (\frac{x}{2} )^{2} ] {} \, \, dx$

= $\int\limits^1_0 {(1 - 2x + x^{2} )} \, \, dx$

= ${(x - x^{2} + \frac{x^{3}}{3} )}\limits^1_0$

= 1 - 1² + $\frac{1^{3} }{3}$ - 0 + 0 - 0

= 1 - 1 + $\frac{1 }{3}$ = $\frac{1}{3}$

So, we get

Volume = $\frac{1}{3}$

7 0

3 years ago