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loris [4]
3 years ago
14

Identify the similar triangles. Find each measure.​

Mathematics
1 answer:
boyakko [2]3 years ago
5 0

Answer:

Example: these two triangles are similar: If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°. So AA could also be called AAA (because when two angles are equal, all three angles must be equal)

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Tom caught a fish that weighed 2/3 pound. Kira caught a fish that weighed 7/8 pound. Whose fish weighed more?
anyanavicka [17]
Tom because his fish is 1.5 pounds and kiras fish is 1.14 pounds
7 0
2 years ago
What is the LCM of 55,121 and 132
serg [7]
132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1

132 = 2^2 * 3 * 11

55121/11 = 5011
5011/5011 = 1

55,121 = 11 * 5011

LCM = common factor with larger exponent * not common factors

LCM = 2^2 * 3 * 11 * 5011

LCM = 661,452
6 0
3 years ago
(A) Write an expression that represents Sarah’s total pay last week. Represent her hourly wage with (w)?
garri49 [273]

Answer:

Step-by-step explanation:

7 0
2 years ago
Find the average rate of change over the interval [-1,2] (from x = -1 to x = 2) for the graph below
Lyrx [107]

Hello!

Find the coordinate where x = -1:

At x = -1, y = 1, so the coordinate is (-1, 1).

Find the coordinate where x = 2:

At x = 2, y = -2, so the coordinate is (2, -2).

Find the rate of change between the points using the slope formula:

slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Plug in the coordinates above:

slope = \frac{-2-1}{2-(-1)}

Simplify:

slope = \frac{-3}{3} = -1

Thus, the rate of change between the points is -1.

8 0
2 years ago
Suppose the heights of a population of people are normally distributed with a mean of 65.5 inches and a standard deviation of 2.
kupik [55]

Answer:

a) P(64.2

b) 69.764

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(65.5,2.6)

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(64.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(64.2

And we can find this probability on this way:

P(-0.50

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

P(-0.50

3) Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=65.5 +1.64*2.6=69.764

So the value of height that separates the bottom 95% of data from the top 5% is 69.764.

5 0
3 years ago
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