A bond is initially bought for $250. It doubles in value every decade.Write an equation relating v, the value of the bond, to d,
1 answer:
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The y values from:
1. ₋6
2. ₋3
3. 0
4. 3
Given the x values and y value as y = 3x
1. when x = ₋2 then y = 3x
y = 3(₋2)
y = ₋6
2. when x = ₋1 then y = 3x
y = 3(₋1)
y = ₋3
3. when x = 0 then y = 3x
y = 3(0)
y = 0
4. when x = 1 then y = 3x
y = 3(1)
y = 3
therefore we get the points as (₋2 , ₋6) (₋1 , ₋3) (0,0) (1 , 3).The graph is pltted and attached.
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Answer:
We conclude that the rule for the table in terms of x and y is:
- y = 3x+2
Step-by-step explanation:
The table indicates that there is constant change in the x and y values, meaning the table represents the linear function the graph of which would be a straight line.
We know the slope-intercept form of the line equation
y = mx+b
where m is the slope and b is the y-intercept.
Taking two points
- (-2, -4)
- (-1, -1)
Finding the slope between (-2, -4) and (-1, -1)
We know that the y-intercept can be determined by setting x = 0 and finding the corresponding y-value.
Taking another point (0, 2) from the table.
It means at x = 0, y = 2.
Thus, the y-intercept b = 2
Using the slope-intercept form of the linear line function
y = mx+b
substituting m = 3 and b = 2
y = 3x+2
Therefore, we conclude that the rule for the table in terms of x and y is:
- y = 3x+2