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yuradex [85]
3 years ago
15

Kim started a lawn mowing business. He charges $5 for each lawn. He bought a lawn mower for $200 and now, after 2 months, has a

profit of $100. How many lawns has he mowed so far?
Mathematics
2 answers:
Bezzdna [24]3 years ago
3 0
<span>5x - 200 = 100 

5x = 100+200 

5x = 300 

</span><span>x = 300/5 

x = 60 

He has mowed 60 lawns so far.</span>
Nina [5.8K]3 years ago
3 0

Answer:

The answer is 60 lawns

Step-by-step explanation:

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The probability of 3 failures or less is about 0.83886, so that is the probability the machine will be working.

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Express 3/5 as a percent
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Answer: 60%

Step-by-step explanation:

3/5 times 20 = 60/100

8 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
What is the following product? 3 root 5 times root 2
Crazy boy [7]

\bf \textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{5}\cdot \sqrt{2}\implies \sqrt[3]{5^1}\cdot \sqrt[2]{2^1}\implies 5^{\frac{1}{3}}\cdot 2^{\frac{1}{2}}\implies 5^{\frac{2}{6}}\cdot 2^{\frac{3}{6}}\implies \sqrt[6]{5^2}\cdot \sqrt[6]{2^3} \\\\\\ \sqrt[6]{25}\cdot \sqrt[6]{8}\implies \sqrt[6]{25\cdot 8}\implies \sqrt[6]{200}

3 0
3 years ago
Read 2 more answers
50 points and BRAINLIEST<br><br> .15m - .13m = 69.96 - 55.96
weeeeeb [17]

Answer:

m=7

Step-by-step explanation:

15m−13m=69.96−55.96

Step 1: Simplify both sides of the equation.

15m−13m=69.96−55.96

15m+−13m=69.96+−55.96

(15m+−13m)=(69.96+−55.96)(Combine Like Terms)

2m=14

2m=14

Step 2: Divide both sides by 2.

2m

2

=

14

2

5 0
3 years ago
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