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3 years ago

A cereal box has a length of 8 inches, a width of 2 inches and a height of 12 inches. What is the volume of the cereal box?

Mathematics

2 answers:

wlad13 [49]3 years ago

7 0

Answer:

192 should be yyour answer

Step-by-step explanation:

DochEvi [55]3 years ago

6 0

Answer:

192 in cubed

Step-by-step explanation:

Multiply 12*2= 24*8

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Work out the time taken, in minutes, for a 68km journey at an average speed of 85km/h

vovikov84 [41]

Answer:

48 minutes

Step-by-step explanation: Time taken is distance divided by speed, so 68/85 is 0.8. 0.8 is equal to 4/5. 4/5 of an hour is 48 minutes.

4 0

3 years ago

Evaluate 9/m +4when m=3

valina [46]

Answer:

Step-by-step explanation:

Put the m value where m is

9/3+4

9/3 simplified is 3

3+4=7

4 0

3 years ago

Read 2 more answers

- 3 + 3x = 2x – 13 <br><br> I have to use more characters...

DENIUS [597]

- 3 + 3x = 2x – 13

Bring -3 to the right side of the equation by adding 3 to both sides

(- 3 + 3) + 3x = 2x – 13 + 3

0 + 3x = 2x - 10

3x = 2x - 10

Bring 2x to the other side by subtracting 2x to both sides

3x - 2x = 2x - 2x - 10

x = -10

Check:

-3 + 3(-10) = 2(-10) - 13

-3 + (-30) = -20 - 13

-33 = -33

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

2 years ago

Can you help me:(( please..

andreev551 [17]

Answer:

it's a non-function

4 0

2 years ago

Use a matrix to solve the system:

Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

$2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\$

Rewrite these equations in matrix form

$\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\$

we can write it like this,

$AX=B\\X=A^{-1}B$

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

$A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right] \\$

now multiply the matrix with B

$X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\$

4 0

2 years ago