PLEASE HELP ME ASAP WILL MARK THE BRAINLEST

Mathematics

2 answers:

koban [17]3 years ago

5 0

Answer:

Step-by-step explanation:

add up the distances from part a,b,c,and d of the hike

Nitella [24]3 years ago

4 0

add up the first row

it would be 20

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Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She

Ghella [55]

Answer:

The correct answer is option (E)

Step-by-step explanation:

Solution to the question

Let us recall from given question that,

H0:p=0.80

Ha:p≠0.80 (which is the two tailed test)

For the p-value we have,

P-value: Let us assume that the null hypothesis is true, then the probability of observing the sample statistics or the more extreme,

Therefore if p= 0.80, the probability of observing or detecting proportion of samples is of at least 0.84 or at most 0.76 is 0.273.

8 0

3 years ago

The graph shows the relationship between the distance a truck can travel and the amount of gasoline used. (5,35) What is the uni

juin [17]

The unit rate is the slope

y=mx+b

m=slope

b=y intercept

equation is y=7x

slope=7

y intercept=0

slope=unit rate because if you use 5 gasoline then you go 5 times 7 miles or 35 miles

The unit rate is 7

Hope I helped :)

8 0

3 years ago

Read 2 more answers

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$