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satela [25.4K]
3 years ago
15

Which graph shows a set of ordered pairs that represent a function?​

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

the third one going from up to down.

Step-by-step explanation:

you have to see if each graph passes the vertical line test, which is no point can be on the same vertical line as another. the only graph without 2 points on the same vertical line is the third one from the top

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Can someone plz teach me step by step, how to do this?
vitfil [10]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
Every year after a new car is
slavikrds [6]

Answer: The value of the car after 3 years is $5,333.333

And no, the relationship is not linear, is an exponential decay.

Step-by-step explanation:

We know that every year, the car loses 1/3 of its value.

So if the initial value of the car is V.

After one year, the new value of the car will be:

Value (1 year) = V - (1/3)*V = (2/3)*V

After another year, the value will be:

Value (2 years) = (2/3)*V - (1/3)*(2/3)*V = V*(2/3)^2

Ok, we already can see that this is an exponential decay.

(So no, this is not a linear relationship).

The value equation as a function of the number of years will be:

Value(N) = V*(2/3)^N

Then if the initial cost of a car is $18,000, and we want to know its value after 3 years, we need to replace V by $18,000 and N by 3 in the above equation:

Value(3) = $18,000*(2/3)^3 = $5,333.333

6 0
3 years ago
Find the value of x. Write your answer in simplest form.
klemol [59]

Answer:

The value of x is 8

Step-by-step explanation:

4 0
3 years ago
Michelle wants ice cream and created a tree diagram to help her organize her options.
Serhud [2]
I think 33.3% that he Chooses that
5 0
3 years ago
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