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Len [333]
3 years ago
13

Helpppppppppppppppppppppp

Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0

Answer:

Step-by-step explanation:

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Leah gets paid $450 a week +5% commission on her sales she hopes to earn at least $600 each week right in any quality to represe
ElenaW [278]

x = sales

450 + 0.05x = 600

5 0
3 years ago
3t+ 7 &gt; 5t + 9<br>last one!!<br>​
wariber [46]

Answer:

Here.....

Step-by-step explanation:

Find the like terms

3t and 5t are like terms

as well as

7 and 9

Take 3t and 5t and add them: 8t

then do the same to  7 and 9: 16

making the answer (8t+16)

Was this helpful?

8 0
3 years ago
Write an equation of the ellipse centered at the origin given its vertex and co vertex Can you please do both
Vika [28.1K]

Answer:

1. \dfrac{x^2}{1}+\dfrac{y^2}{4}=1.

2. \dfrac{x^2}{121}+\dfrac{y^2}{100}=1.

Step-by-step explanation:

The equation of the ellipse is

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\ (a>b)

or

\dfrac{x^2}{b^2}+\dfrac{y^2}{a^2}=1\ (a

1. If the vertex of the ellipse is at point (0,2), then b=2.

If the co-vertex of the elllipse is at point (-1,0), then a=1.

The equation of the ellipse is

\dfrac{x^2}{1^2}+\dfrac{y^2}{2^2}=1,

\dfrac{x^2}{1}+\dfrac{y^2}{4}=1.

This ellipse has foci on y-axis.

2. If the vertex of the ellipse is at point (-11,0), then a=11.

If the co-vertex of the elllipse is at point (0,10), then b=10.

The equation of the ellipse is

\dfrac{x^2}{11^2}+\dfrac{y^2}{10^2}=1,

\dfrac{x^2}{121}+\dfrac{y^2}{100}=1.

8 0
4 years ago
Which graph represents a function?
enyata [817]

Answer:

D, the horizontal line is a function

Step-by-step explanation:

To pass the vertical line test, a vertical line cannot go through the function more than once

A is a vertical line so it will fail the vertical line test

B will fail the vertical line test at many points.  One example is at

x =0 where you can see it will intersect at two points

C will fail the vertical line test at many points.  One example is at

x =0 where you can see it will intersect at two points

D is a horizontal line.  This will pass the vertical line test

3 0
3 years ago
Fill in the blank.
gladu [14]

The ____ is used to determine the left-hand and right-hand behavior of the graph of a polynomial function.

When largest exponent of the polynomial is even and leading coefficient is positive , then left hand and right hand ends of the graph goes up

When largest exponent of the polynomial is even and leading coefficient is negative , then left hand and right hand ends of the graph goes down

When largest exponent of the polynomial is odd and leading coefficient is positive , then left hand graph goes down and right hand ends of the graph goes up

When largest exponent of the polynomial is odd and leading coefficient is negative , then left hand graph goes up and right hand ends of the graph goes down

Hence, Leading coefficient test is used to determine the left-hand and right-hand behavior of the graph of a polynomial function.

5 0
3 years ago
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