30.597/47 please help me

25 points for this please help with step by step

Svetllana [295]

a) 20.9

The mean is calculated by adding up the scores and dividing the total by the number of scores, it is also called the average.

First, we can count and see there are 11 players (makes sense for a football team). Adding up the ages gives us 19 + 19 + 20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23 = 230. Divide by 11 and we get a mean of of about 20.9!

b) 30

To figure this out, we will set up an equation that looks like this:

$\frac{19 + 19 + 20 + 20 + 20 + 21 + 22 + 22 + 22 + 22 + 23+x}{12} =22$

And now we will solve:

[multiply both sides by 12] 230 + x = 264

[subtract 130 from both sides] x = 30

So the age of the new player should be 30!

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0

2 years ago

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A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy

aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) $\bar{B}$ y $P(\bar{B})$ =0.5 (c) $\bar{A}$ ∪ $\bar{B}$ y P( $\bar{A}$ ∪ $\bar{B}$ ) = 0.9 (d) $\bar{A}$ ∩ $\bar{B}$ y P( $\bar{A}$ ∩ $\bar{B}$ )=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P( $A\cap \bar{B}$ ) = 0.3, P( $B\cap \bar{A}$ ) = 0.4 and P( $A\cap B$ ) = 0.1

(a) P(A) = P( $A\cap (B\cup\bar{B})$ ) = P( $A\cap B$ ) + P( $A\cap \bar{B}$ ) = 0.1 + 0.3 = 0.4

(b) P(B) = P( $B\cap (A\cup\bar{A})$ ) = P( $B\cap A$ ) + P( $B\cap \bar{A}$ ) = 0.1 + 0.4 = 0.5

P( $\bar{B}$ ) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e., $\bar{A}$ , and the customer does not buy from outlet 2 is the complement of B, i.e., $\bar{B}$ , so, the customer does not buy from outlet 1 or does not buy from outlet 2 is $\bar{A}$ ∪ $\bar{B}$ and P( $\bar{A}$ ∪ $\bar{B}$ ) = P( $(A\cap B)^{c}$ ) by De Morgan's laws

P( $(A\cap B)^{c}$ ) = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to $\bar{A}$ ∩ $\bar{B}$ and P( $\bar{A}$ ∩ $\bar{B}$ ) = P( $(AUB)^{c}$ ) by De Morgan's laws, and

P( $(AUB)^{c}$ ) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0

2 years ago

6x-2(-3x-5)=154 What the answer

Fofino [41]

Answer:

x = 12

Step-by-step explanation:

Simplifying

6x + -2(-3x + -5) = 154

Reorder the terms:

6x + -2(-5 + -3x) = 154

6x + (-5 * -2 + -3x * -2) = 154

6x + (10 + 6x) = 154

Reorder the terms:

10 + 6x + 6x = 154

Combine like terms: 6x + 6x = 12x

10 + 12x = 154

Solving

10 + 12x = 154

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.

10 + -10 + 12x = 154 + -10

Combine like terms: 10 + -10 = 0

0 + 12x = 154 + -10

12x = 154 + -10

Combine like terms: 154 + -10 = 144

12x = 144

Divide each side by '12'.

x = 12

Simplifying

x = 12

7 0

2 years ago

Analyze the diagram below and complete the instructions that follow. Find sin L

Alja [10]

Answer:

Step-by-step explanation:

By Pythagoras Theorem,

OM = √(4² + 3²) = √(16 + 9) = √25 = 5

And,

OL = √(12² + 5²) = √(144 + 25) = √169 = 13

Now,

sin L = $\frac{Perpendicular}{Hypotenuse}$ = $\frac{5}{13}$ = 0.384

4 0

2 years ago

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The ratio of the perimeters of two rectangles is 5 to 8. The perimeter of the larger rectangle is 72 inches. What is the perimet

navik [9.2K]

P (smaller) : P (larger) = 5 : 8
P (larger) = 72 in
P s : 72 = 5 : 8
8 P s = 72 * 5
8 P s = 360
P s = 360 : 8
P s = 45 in
Answer:
The perimeter of the smaller rectangle is 45 inches.

7 0

2 years ago

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