Answer:
The dimensions of the yard are W=20ft and L=40ft.
Step-by-step explanation:
Let be:
W: width of the yard.
L:length.
Now, we can write the equation of that relates length and width:
(Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
(Equation #2)
Since the Area of the yard is 
, then equation #2 turns into:
Now, we rearrange this equation:
We can divide the equation by 5 :
We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since 
and 
. The equation factorised looks like this:
Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:
Therefore, the dimensions of the yard are W=20ft and L=40ft.
Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
Answer: 120.5 shares
Step-by-step explanation: You add 68.38 and 57.12 and there is you answer
Answer:
(0,-5)
Step-by-step explanation:
You just have to find the middle of each one
From -8 to 8 there are 16 numbers so you divide 16 by 2 which would be 8 and add that to -8 giving you 0
From -10 to 0 there are 10 numbers divided by 2 is 5 so you add 5 to -10 giving you -5
This makes your midpoint (0,-5)
Answer:
45
Step-by-step explanation:
