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2 years ago

What is z+6+z-11=z+49

Mathematics

1 answer:

aleksklad [387]2 years ago

4 0

Answer:

z=18

Step-by-step explanation:

z+6+z-11=z+49

2z-5=z+49

3z-5=49

3z=54

z=18

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There are 52 cars in the movie theater parking lot. 12 more cars parked in the parking lot before the movie started but 3 cars l

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Answer:

Step-by-step explanation:

52 + 12 = 64

64-3 that left is 62 cars in the parking lot

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2 years ago

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Solve for x ~<br><img src="https://tex.z-dn.net/?f=4x%20-%2016%20%3D%2064" id="TexFormula1" title="4x - 16 = 64" alt="4x - 16 =

Naddika [18.5K]

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve for x ~

$\qquad \sf \dashrightarrow \:4x - 16 = 64$

$\qquad \sf \dashrightarrow \:4(x - 4) = 64$

$\qquad \sf \dashrightarrow \:(x - 4) = 64 \div 4$

$\qquad \sf \dashrightarrow \:x - 4 = 16$

$\qquad \sf \dashrightarrow \:x = 16 + 4$

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2 years ago

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At winds speeds above 1000 centimeters per second (cm/sec), significant sand-moving events begin to occur. Wind speeds below 100

alisha [4.7K]

Answer:

Lower limit = 1007.95 cm/s

Upper limit = 1142.05 cm/s

Step-by-step explanation:

We have to calculate a 95% CI with population's standard deviation known.

The sample is size n=60, with mean M=1075.

The confidence interval can be expressed as:

$M-z*\sigma/\sqrt{n} \leq\mu\leq M+z*\sigma/\sqrt{n}$

For a 95% CI, the value of z=1.96.

$1075-1.96*265/\sqrt{60} \leq\mu\leq 1075+1.96*265/\sqrt{60} \\\\1075-67.05 \leq\mu\leq 1075+67.05\\\\ 1007.95 \leq\mu\leq 1142.05$

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2 years ago

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

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Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

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Then the equation of the parabola becomes:

$y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18$

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2 years ago

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Answer: Rigid motion is otherwise known as a rigid transformation and occurs when a point or object is moved, but the size and shape remain the same. This differs from non-rigid motion, like a dilation, where the size of the object can increase or decrease

Step-by-step explanation:

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2 years ago