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Wittaler [7]
2 years ago
10

If ∠A > ∠B, then what is the relation between AC and BC?​

Mathematics
2 answers:
prohojiy [21]2 years ago
8 0

Answer:

ab and ac are congruent with each other

Travka [436]2 years ago
6 0

Answer:

BC > AC

Step-by-step explanation:

∠A > ∠B (Given)

Side opposite to larger angle is larger and side opposite to smaller angle is smaller.

->AC < BC

or

BC > AC

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3 years ago
A rectangle has a perimeter of 150 feet and a base of 45 feet. What is the height?
frez [133]

Answer:

30

Step-by-step explanation:

45+45 = 90

150-90 = 60

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What are the coordinates of point P on this graph?
GarryVolchara [31]

Answer:

The coordinates are 6,5.

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a2 + b2 = c2, which in this iso
abruzzese [7]

Complete Question

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

a) substitute values for a and c into the original pythagorean theorem equation.

b) divide both sides of the equation by two, then determine the principal square root of both sides of the equation.

c) determine the principal square root of both sides of the equation.

d) divide both sides of the equation by 2.

Answer:

c) determine the principal square root of both sides of the equation.

Step-by-step explanation:

Pythagoras Theorem for a right angled triangles states that:

a²+ b²= c²

But for an Isosceles Triangle, where two sides of the triangle are equal, we have:

a²+ a² = c²

By combining like terms

2a² = c²

We square root both sides of the equation.

√2a² = √c

√2a² = c

The final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg = √2a² = c is Option c.

4 0
3 years ago
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Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x​
Tanzania [10]

Recall that

\cosh^2(x) - \sinh^2(x) = 1

Dividing both sides by cosh²(x) gives

1 - \tanh^2(x) = \mathrm{sech}^2(x)

Also, recall the identity

\sinh(2x) = 2\sinh(x)\cosh(x)

Then

\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)

4 0
3 years ago
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