Answer:
I agree in this song because being a farmer is not easy you need to be hardwork
Answer:
public class Main
{
public static void main(String[] args) {
int carYear = 1995;
if(carYear < 1967)
System.out.println("Probably has few safety features.");
if(carYear > 1971)
System.out.println("Probably has head rests.");
if(carYear > 1992)
System.out.println("Probably has anti-lock brakes.");
if(carYear > 2002)
System.out.println("Probably has tire-pressure monitor.");
}
}
Explanation:
The code is in Java.
Initialize the carYear
Use if statements to handle year before 1967, after 1971, after 1992 and after 2002.
Print the required message for each if statement
I believe that the answer to fit this sentence is chart. Hope that this answer helped! ☺
A composite primary key applies to more than one field. <span>A table can have only one primary key, which may consist of single or multiple fields.</span>
A composite primary key is selected from Design view. <span>In Design </span>view<span>, you can use the </span>Primary Key<span> button to assign or remove the </span>primary key<span> designation for the </span>selected<span> field or fields.</span>
Answer:
- low = 10
- high = 50
- count = 0
-
- for i in range(low, high + 1):
- if(i % 3 == 0 and i % 5 == 0):
- count += 1
- print(count)
Explanation:
The solution code is written in Python.
We can create low and high variables to store the lower bound and upper bound in the range (Line 1-2)
Next create a counter variable, count (Line 3).
Use a for loop to traverse through the number between lower bound and upper bound and check if the current number-i is divisible by 3 and by 5, increment the count by one.
After the loop, print the count and we can get the number of ideal integers within the range (Line 8).
