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Minchanka [31]
3 years ago
15

A box contains orange balls and green balls. The number of green balls is seven more than three times the number of orange balls

. If there are 67 balls altogether, how many green balls and how many orange balls are there in the box?
Mathematics
1 answer:
OverLord2011 [107]3 years ago
3 0

Answer:

52 green, 15 orange

Step-by-step explanation:

g + o = 67   g = green, o = orange, x = total

g = 3o + 7

use substitution: (3o + 7) + o = 67

solve for o:

4o + 7 = 67

4o = 60

o = 60/4 = 15

solve for g:

g + 15 = 67

g = 52

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If 20 is decreased to 18.6, the decrease is what percent of the original number?
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Answer:

D) y = -1/2x + 4

Step-by-step explanation:

Points on the graph: (0, 4) and (8, 0)

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m=(0 - 4)/(8-0)

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m = -1/2

Slope-intercept:

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What are the coordinates of R’, the image of R(-4,3) after a reflection in the line y=x?
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Answer:

R'(3,-4)

Step-by-step explanation:

we know that

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places

so

The rule of the reflection across the line y=x is equal to

(x,y) ------> (y,x)

we have

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6 0
2 years ago
R is inversely proportional to A.
hjlf

Here are the answer: a) R = 3.6 and b) A = 2

Step-by-step explanation:

Given,

R is inversely proportional to A.

R ∝ \frac{1}{A}

so, R = \frac{k}{A}  -------eq 1 where k is any constant

To find the values of a) R when A = 5 and

b) Value of A when R = 9

Now,

Putting R = 12 and A = 1.5 in eq 1 we get,

12 = \frac{k}{1.5}

or, k = 12×1.5 = 18

From eq 1 we get,

R = \frac{18}{A} --------- eq 2

Now,

a) Putting A= 5 in eq 2 we get,

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b)  Putting R = 9 in eq 2 we get

R = \frac{18}{A}

or, A = \frac{18}{9} = 2

5 0
3 years ago
Read 2 more answers
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