Answer:
That's strange. (-1/2, 5) would work for both if only the top equation had a less than or equal to sign. If all else fails, just puts c as your answer lol
Step-by-step explanation:
Answer:
6:15
Step-by-step explanation:
6:15 is half of 6:30
Answer: m∠ TUW = 38°
m∠WUV = 12°
m∠TUV = 103°
Step-by-step explanation:
Given: m∠ TUW = (5x + 3)°, m∠WUV=(10x-5)°, and m∠TUV=(17x-16)°
Since, m∠TUV = m∠ TUW + m∠WUV
So, 17X-16 = (5x + 3) + (10x-5)
⇒ 17X-16 = 5x + 3 + 10x-5 [open parenthesis]
⇒ 17X-16 =5x + 10x +3 -5 [combine like trems]
⇒ 17X-16 =15x -2
⇒ 17X -15x = -2+16 [subtract 15x and add 16 on both sides]
⇒ 2x = 14
⇒ x= 7 [divide both sides by 2]
Now, m∠ TUW = (5(7) + 3)°= 38°
m∠WUV=(10(7)-5)° = 12°
m∠TUV=(17(7)-16)° = 103°
Hence, m∠ TUW = 38°
m∠WUV = 12°
m∠TUV = 103°
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;
)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤
)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!