Answer:
Photo 1: (a) C
(b) A
(c) D
Photo 2: 12.0416cm
Photo 3: 15.5242cm
Step-by-step explanation:
Photo 1: (a) 6×4=24
(b) 6(5)+6=36
(c) 6×6=36
Photo 2: Using Pythagoras' Theorem,
Unknown side length= square root symbol [(8×8)+(9×9)]
= 12.0416cm (6sf)
Photo 3: Using Pythagoras' Theorem,
AC= square root symbol (AB^2+BC^2)
=square root symbol [(15×15)+(4×4)]
= 15.5242cm (6sf)
Answer:
The answers B.
Step-by-step explanation:
Answer:
The data we have is:
The acceleration is 3.2 m/s^2 for 14 seconds
Initial velocity = 5.1 m/s
initial position = 0m
Then:
A(t) = 3.2m/s^2
To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.
V(t) = (3.2m/s^2)*t + 5.1 m/s
To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)
P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t
Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.
P(14s) = (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m
So the final position is 385 meters ahead the initial position.
Step-by-step explanation:
finding for 3√512
=67.882250993908562
rounded to the n nearest whole number=68
I think BEA is adjacent to it