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4vir4ik [10]
3 years ago
12

Ludovica creates flash cards for her vocabulary words.She creates 3 more cards per noun.

Mathematics
1 answer:
ella [17]3 years ago
7 0

Answer: what is the whole question angel?


Step-by-step explanation:


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Given sin theta=5/13 and cos theta=12/13, which of the following can be proven using a Pythagorean identity?
ZanzabumX [31]

Answer:

4th option

Step-by-step explanation:

given

sinΘ = \frac{5}{13} and cosΘ = \frac{12}{13} , then

( \frac{5}{13} )² + ( \frac{12}{13} )²

= \frac{25}{169} + \frac{144}{169}

= \frac{25+144}{169}

= \frac{169}{169}

= 1

showing sin²Θ + cos²Θ = 1

4 0
2 years ago
I need help with this division problem 1 divide by 3.0
sertanlavr [38]

Answer:

0.333333

Step-by-step explanation:

3 0
3 years ago
Entomologists are biological scientists who study insects. Entomologists studying tree
liraira [26]

Answer:

C(T) = 0, T \leq 45\\~~~~~~~~= 3.6T - 162, T > 45

Cricket will make 198 chirps per minute when temperature is 100 degrees.

Step-by-step explanation:

We are given the following in the question:

a) The number of chirps per minute, C, that the tree cricket makes is linearly dependent on  the temperature, T, in Fahrenheit.

Let this relation be given by the linear equation:

C(T) = aT + b

where a and b are constants.

The crickets do not chirp at all below 45 degrees.

C(T) = 0, T \leq 45\\~~~~~~~~= aT + b, T > 45

When the temperature is 45 degrees, C(T) = 0

Thus, we can write,

0 = 45a + b

At 85 degrees they chirp about 144 times per minute.

144 = 85a + b

Solving the equation, we get,

144-0 = 40a\\\\a = \dfrac{144}{40} = 3.6\\\\144 = 85(3.6) + b\\b = -162

C(T) = 0, T \leq 45\\~~~~~~~~= 3.6T - 162, T > 45

b) chirps per minute will crickets make at 100 degrees

We put T = 100 in the above equation,

C(T) = 3.6(100) -162 = 198

Cricket will make 198 chirps per minute when temperature is 100 degrees.

6 0
3 years ago
Factor: 15c^2 +37c +20
Masteriza [31]

Answer:

(5 c + 4) (3 c + 5)

Step-by-step explanation:

Factor the following:

15 c^2 + 37 c + 20

Factor the quadratic 15 c^2 + 37 c + 20. The coefficient of c^2 is 15 and the constant term is 20. The product of 15 and 20 is 300. The factors of 300 which sum to 37 are 12 and 25. So 15 c^2 + 37 c + 20 = 15 c^2 + 25 c + 12 c + 20 = 5 (5 c + 4) + 3 c (5 c + 4):

5 (5 c + 4) + 3 c (5 c + 4)

Factor 5 c + 4 from 5 (5 c + 4) + 3 c (5 c + 4):

Answer: (5 c + 4) (3 c + 5)

7 0
3 years ago
If the price goes from $25 to $18, what percent was the discount?
marissa [1.9K]

Answer:

28%

Step-by-step explanation:

I just used a calculator and got it lmbo

25-28%

6 0
4 years ago
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