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alexandr402 [8]
3 years ago
14

What is the value of -32+(-4+7)(2)? -28 -3 3 15

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer:

-26

Step-by-step explanation:

  1. -32+3×2
  2. -32+6
  3. -26

By using BODMAS, any of the answers given is correct!

vekshin13 years ago
6 0

Answer:

-28

Becuase:

-32+(-4+7)(2)

Step-by-step explanation:

-32+(-4+7)(2)

-32+(3)(2)

-32+6

-26

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I’m confused how do you solve 378 divided by 6 like I know that it’s it 63 but how do you solve it
KatRina [158]

378 divided by 6 is 63

That is the solution. 63 is the final answer. You could mix it around to make sure and say... 6 times 63 equals 378

But there is no more than 63

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adoni [48]
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easch cube inside the rectangle prism has a edge length of 3/4 inch what is the volume of the rectangle prism
vfiekz [6]

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Done.

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Write a recursive formula for the sequence 6,10,14,18,22,.The find the next term
Assoli18 [71]

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3 years ago
The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
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