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Dimas [21]
3 years ago
7

Mary makes f dollars the first day of her new job. She makes $25 ¾ the second day of her job. In total, Mary made $60.00. Solve

the equation f + 25.75 = 60 to find how much money Mary made on her first day.
Mathematics
2 answers:
Whitepunk [10]3 years ago
7 0
All you have to do is: 60-25.75 = 34.25.

f = 34.25
mars1129 [50]3 years ago
7 0

f + 25.75 = 60 | - 25.75 \\ f + 25.75 - 25.75 = 60 - 25.75 \\ f = 34.25

Answer: On the 1st day Mary made $34.25

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Answer:

<em>It will take 12 hours to fill the tank</em>

Step-by-step explanation:

Proportions

Tap A fills a tank in 4 hours. It means each hour it fills 1/4 of the tank.

Tap B fills the tank in 3 hours. Each hour it fills 1/3 of the tank.

Tap C empties the tank when full in 2 hours. Each hour it empties 1/2 of the tank.

Each hour, the tank gets filled by:

\displaystyle \frac{1}{4}+\frac{1}{3}-\frac{1}{2}=\displaystyle \frac{3}{12}+\frac{4}{12}-\frac{6}{12}=\frac{3+4-6}{12}=\frac{1}{12}

Since the tank fills 1/12 of its capacity in one hour, it follows that it will take 12 hours to fill the tank

6 0
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Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo
Likurg_2 [28]

Answer:

The given equation is

25x^{2} +4y^{2}=100

Which represents an elipse.

To find its elements, we need to divide the equation by 100

\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1

Where a^{2} =25 and b^{2}=4. Remember that the greatest denominator is a, and the least is b. So, we extract the square root on each equation.

a=5 and b=2.

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is 2a=2(5)=10.

The length of the minor axis is 2b=2(2)=4.

The vertices are (0,5);(0,-5) and (2,0);(-2,0).

Now, the main parameters of an elipse are related by

a^{2}=b^{2} +c^{2}, which we are gonna use to find c, the parameter of the focus.

c=\sqrt{a^{2}-b^{2} }=\sqrt{25-4}=\sqrt{21}

So, the coordinates of each focus are (0,\sqrt{21}) and (0,-\sqrt{21})

The eccentricity of a elipse is defined

e=\frac{c}{a}=\frac{\sqrt{21} }{5}  \approx 0.92

The latus rectum is defined

L=\frac{2b^{2} }{a}=\frac{2(4)}{5} =\frac{8}{5} \approx 1.6

Finally, the graph of the elipse is attached.

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