Supposing you want this equation to be solved for a: we start with
![-\dfrac{a}{5}+21=23](https://tex.z-dn.net/?f=-%5Cdfrac%7Ba%7D%7B5%7D%2B21%3D23)
Subtract 21 from both sides:
![-\dfrac{a}{5}=2](https://tex.z-dn.net/?f=-%5Cdfrac%7Ba%7D%7B5%7D%3D2)
Multiply both sides by 5:
![-a=10](https://tex.z-dn.net/?f=-a%3D10)
Change sign to both sides:
![a=-10](https://tex.z-dn.net/?f=a%3D-10)
<h3>The exact probability that the blue ball is drawn first and the red ball is drawn second is
![\frac{1}{132}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B132%7D)
</h3>
<em><u>Solution:</u></em>
<em><u>The probability of an event is given as:</u></em>
![Probability = \frac{ \text{ number of favorable outcomes }}{ \text{ total number of possible outcomes }}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B%20%5Ctext%7B%20number%20of%20favorable%20outcomes%20%7D%7D%7B%20%5Ctext%7B%20total%20number%20of%20possible%20outcomes%20%7D%7D)
Given that,
There are 12 balls in a bag
One is blue and one is red
Favorable outcome = blue ball is drawn first
Favorable outcome = 1
Therefore,
![Probability = \frac{1}{12}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B12%7D)
Now, without replacement, red ball is drawn second
Therefore,
Total possible outcomes = 12 - 1 = 11
![Probability = \frac{1}{11}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B11%7D)
<em><u>What is the exact probability that the blue ball is drawn first and the red ball is drawn second?</u></em>
![Total\ probability = \frac{1}{12} \times \frac{1}{11} = \frac{1}{132}](https://tex.z-dn.net/?f=Total%5C%20probability%20%3D%20%5Cfrac%7B1%7D%7B12%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7B11%7D%20%3D%20%5Cfrac%7B1%7D%7B132%7D)
Thus the exact probability that the blue ball is drawn first and the red ball is drawn second is ![\frac{1}{132}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B132%7D)
Answer:
$381.29
Step-by-step explanation:
10000(1+.18)5
10000(1.18)5
Amount due $22877.58
since 5 years x 12 months =60 months
monthly payment is 22877.58÷60 = $381.29
Answer:
Try distributing numbers by multiplying
Plural because it has eaten