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Svetach [21]
3 years ago
7

If you travel at a rate of 45 miles per hour how many minutes will it take to travel one mile

Mathematics
1 answer:
makkiz [27]3 years ago
4 0
it will take 60 minutes to travel 1 mile per hour
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The scatter plot below shows a linear association. Which is the best linear model for the data?
Ivanshal [37]

Answer:

ye its y=5x-10

Step-by-step explanation:

7 0
3 years ago
4 What is the solution to the inequality -3x-42>3 ?
Vladimir [108]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is the solution to the inequality -3x-42>3 ?

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

- 3 x - 42 \gt 3

Add 42 to both sides.

-3x>3+42

Add 3 and 42 to get 45.

-3x>45

Divide both sides by -3. As -3 is <0, the inequality direction has changed.

x

Divide 45 by -3 to get -15.

\huge \boxed{ \boxed{ \bf \: x

8 0
2 years ago
Simplify the following expression -5[(x^3+1)(x+4)]
katrin [286]

Answer:

B

Step-by-step explanation:

-5[ (x³+1)(x+4) ] = -5[ x³*(x+4) + 1*(x+4) ]

      = -5 [ x³*x + x³*4 + 1*x + 1*4 ]

      = -5 [ x⁴ + 4x³ + x + 4]

      = -5*x⁴ + (-5)*4x³ + (-5)*x + (-5) * 4

      = -5x⁴ - 20x³ - 5x - 20

4 0
2 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
3 years ago
Factor by Grouping:<br> 8x²+12x+2xy+3y
Yuliya22 [10]

Answer:

(2x +3) (4x +y)

Step-by-step explanation:

refer the image

3 0
2 years ago
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