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3 years ago

If you travel 342 miles and arrive to your house in 6 hours how fast were they traveling?

2 answers:

6 0

Hello there!

They/You were traveling 57 miles per hour (mph) because 342 divided by 6 = 57.

Have an awesome and successful day! -Wajiha

sladkih [1.3K]3 years ago

5 0

They were traveling 57 mph

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Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

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1 year ago

–8(n + 7) >-96??????????????

mihalych1998 [28]

Answer:

D) n<5

Step-by-step explanation:

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anzhelika [568]

Answer: Yes, it is a real number. 3.4 is a rational number and rational numbers are real numbers. So 3.4 is a real number.

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2 years ago

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Masja [62]

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2 years ago

(x+3)(x−3)<br> In polynomial standard form

ozzi

Answer:

(x^2-9)

Step-by-step explanation:

Well, using FOIL you can put an polynomial in standard form.

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2 years ago