I have seen this question before and I think you meant 10 more dimes than nickels.
We can use substitution to answer this question. The value of a nickel is 5 cents, and we can use the variable n to represent the number of nickels. The value of a dime is 10 cents, and we can use the variable d to represent the number of dimes.
First lets figure out the equations.
.10d+.5n=2.80 (the number of nickels (n) multiplied by .5 will tell us their money value. Same thing for the dimes)
d-n=10 (since there are 13 more dimes than nickels, the number of dimes value (d) minus the number of nickels value (n) will give us 10)
Now lets isolate a variable in one of the equations, preferably the second one because it doesn't have any visible coefficients,
d-n=10
-n=10-d (subtracted the d from both sides)
n=-10+d (made the n positive)
Now that we have the value of n, we can plug it into the other equation.
.10d+.05n=2.80
.10d+.05(-10+d)=2.80 (we replaced the n with the value that we previously got)
.10d-.5+.05d=2.80 (did the multiplication)
.15d-.5=2.80 (combined like terms)
.15d=3.30 (added the .5 to both sides)
d=22 (divided both sides by the .15)
Now that we know that there are 22 dimes and we also know that there are 10 less nickels than dimes, so we can subtract 10 from 22 to get the number of nickels. 22-10=12
d=22
n=12
1.3 times 10 is 13 and 13 to the 15th power is 51185893014090760
<span>First year is 30,000.
</span><span>Earn 5% raise every year.
</span>Growth factor is 1.05 this sounds a lot like a geometric ratio.
An = A1 × r^(n-1)Sn = A1 × (1 - r^n) / (1-r)<span>n = 40
A1 = 30,000
A40 = $30,000 * 1.05^39 = $201,142.53
S40 = A1 * (1 - 1.05^40) / (1-1.05) which becomes:
S40 = 30,000 * -6.039988712 / -.05 which becomes:
</span>S40 = -181,199.6614 / -.05 which becomes:
S40 = $3,623,993.227
<span>The individual yearly calculations are shown below: </span>
Answer: P(odd) = 0.499
Step-by-step explanation:
Given:
Total number of people = 20
Number of men = 12
Number of women = 8
Number of jury to be selected = 6
For the jury to have an odd number of women. it must have either of the three.
1. 1 woman , 5 men
2. 3 women, 3 men
3. 5 women, 1 man
The total possible ways of selecting the 6 people jury is;
N = 20C6 = 20!/6!(20-6)!
N = 38760
The possible ways of selecting;
Case 1 : 1 woman, 5 men
N1 = 8C1 × 12C5
N1 = 8 × 792 = 6336
Case 2 : 3 women , 3 men
N2 = 8C3 × 12C3
N2 = 12320
Case 3 : 5 women, 1 man
N3 = 8C5 × 12C1
N3 = 672
P(Odd) = (N1+N2+N3)/N
P(odd) = (6336+12320+672)/38760
P(odd) = 19328/38760
P(odd) = 0.499
there are 6 faces multiply 25 by 6
25*6=150cm^2
