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yawa3891 [41]
3 years ago
7

In a random sample of high school seniors, the proportion who use text messaging was 0.88. In a random sample of high school fre

shmen, this proportion was 0.68. Researchers found the difference in proportions to be statistically significant and obtained one of the following numbers for the p-value. Which is it?
a. 1.5
b. 0.02
c. 0.78
d. 0.30
Mathematics
1 answer:
Bond [772]3 years ago
5 0

Answer:

b. 0.02

Step-by-step explanation:

The smaller the p-value, the stronger the evidence that you should reject the null hypothesis. In this case, this will mean rejecting that the proportions are not significantly different.

Usually, a p-value is considered to be statistically significant when p ≤ 0.05.

From the answer options provided, alternative b. 0.02 is the only one that represents the difference in proportions to be statistically significant (there is only a 2% chance that the proportions are not significantly different).

Therefore, the answer is b. 0.02

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julia-pushkina [17]

Money earned by restaurant on Friday=$1073

Money earned by restaurant on Saturday=$1108

Let Money earned by restaurant on Sunday=$x

Average=$1000

\text { average}=\frac  { sum of all the observation}{total number of observation}

Number of observation=3

                           ⇒  3×  1000=1073+1108+x

                            ⇒3000=     2 181+x

                              ⇒3000-2181=x

                            ⇒x=819

The restaurant needs to earn on Sunday to average $1000 per day over the three-day period=$819


6 0
3 years ago
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Need help ASAP with this question please
Assoli18 [71]

Answer:

4th option, 5 5/6

Step-by-step explanation:

8 1/2 - 2 2/3

= 17/2 - 8/3

= (51-16)/6

= 35/6

= 5 5/6

Answered by GAUTHMATH

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3 years ago
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Dmitrij [34]
The answer is choice A- 68
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Suppose the total benefit of watching 1 baseball game is 100, the total benefit of watching 2 games is 120, and the total benefi
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Answer:

A. 5

Step-by-step explanation:

The marginal benefit of an article, B_m is calculated as:

B_m=\frac{DB_t}{DQ}

Where DB_t is the change in the total benefit of the article, and DQ is the change in the units of the article.

If we want to know the marginal benefit of watching the 3rd game, we need to use the information of total benefit of watching 2 games and 3 games.

In this case, the total benefit of watching 2 games is 120 and the total benefit of watching 3 games is 125, so DB_t and DQ are equal to:

DB_t=125-120=5

DQ = 3 - 2 = 1

Then, the marginal benefit of watching the third game is:

B_m=\frac{5}{1}=5

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Answer:

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Step-by-step explanation:

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