Type the correct answer in each box.

In attachments/ Please help me!!!/Brainlist!!!!

miss Akunina [59]

If my calculations are correct the answer is cut your answer in half

7 0

1 year ago

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On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).

Vlad1618 [11]

Answer:

Area of parallelogram ABCD=13.05=13 Sq.Units

Step-by-step explanation:

Given;

A(3,6) B(6,5) C(5,1) and D(2,2)

are points for parallelogram

To Find:

Area of Parallelogram ABCD

Solution:

By using distance formula we can calculate for each length of parallelogram

But by property of parallelogram

Opposite side are parallel and equal in length

So AB|| DC i.e AB=DC

And AC|| BD i.e BD=AC

Hence I.e Dist(AB)=Dist(DC)

Now construct the ABCD parallelogram ,on graph so as to find angle made by parallelogram with plane .

(Refer the attachment)

Now

Distance of AD=Sqrt[(2-3)^2+(2-6)^2]

=Sqrt[1+16]

=4.123

Similarly for AB=Sqrt[(6-3)^2+(5-6)^2]

=Sqrt[9+1]

=3.16

ABOVE VALUES ARE SAME AS GRAPH (REFER THE ATTACHMENT)

Now ,angle made by parallelogram with plane and it is 90 degree i.e the

Now Area of parallelogram(ABCD)=a*b*sinФ

here a=4.123 units and b=3.16 units and Ф=90

Area of parallelogram=3.167*4.123*sin90

=3.167*4.123

=13.05 sq. units

3 0

2 years ago

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What equation is graphed in this figure?

Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

$(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})$

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.

7 0

1 year ago

Please help me!!! :(

PSYCHO15rus [73]

Answer:

$15.75x^{10}y^{19}$

Step-by-step explanation:

To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.

After applying the binomial theorem and simplifying, you should get:

$512x^{18}y^{27}-576x^{16}y^{25}+288x^{14}y^{23}-84x^{12}y^{21}+\frac{63x^{10}y^{19}}{4}-\frac{63x^8y^{17}}{32}+\frac{21x^6y^{15}}{128}-\frac{9x^4y^{13}}{1024}+\frac{9x^2y^{11}}{32768}-\frac{y^9}{262144}$

Our 5th term here is: $\frac{63x^{10}y^{19}}{4}$ which is equal to $15.75x^{10}y^{19}$

~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~

4 0

2 years ago

You start driving north for 3 miles, turn right, and drive east for another 4 miles. At

Elanso [62]

Answer:

The straight line distance is 5 miles from starting point

Step-by-step explanation:

7 0

2 years ago